echo "$REPOS" | jq '.[].repositoryName' | while read -r repo; do echo "do something with $repo"; done

输出：

do something with "repo_a"
do something with "repo_b"
do something with "repo_c"
do something with "repo_d"

或者不加引号：

echo "$REPOS" | jq -r '.[].repositoryName' | while read -r repo; do echo "do something with $repo"; done

输出：

do something with repo_a
do something with repo_b
do something with repo_c
do something with repo_d

我发现问题了……此命令：

REPOS=$(aws codecommit list-repositories)

返回一个json，如下所示：

{
  "repositories": [
  {
    "repositoryName": "repo_a",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_b",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_c",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_d",
    "repositoryId": "XXXXXX"
  }
]
}

我没有考虑jq中的“repositories”字段。
这个脚本现在运行良好：

REPOS=$(aws codecommit list-repositories)

echo $REPOS | jq -r '.repositories[].repositoryName' | while read name ; do
    git clone ssh://git-codecommit.us-east-1.amazonaws.com/v1/repos/$name
done

感谢您的支持。祝你有个美好的一天：）

如果你想迭代JSON值而不是单个字段值，你可以使用-c选项，这样你就可以每行得到一个JSON元素：

repositories='{
  "repositories": [
  {
    "repositoryName": "repo_a",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_b",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_c",
    "repositoryId": "XXXXXX"
  },
  {
    "repositoryName": "repo_d",
    "repositoryId": "XXXXXX"
  }
]
}'

while read repository
do
  name=$(echo "$repository" | jq -r .repositoryName)
  id=$(echo "$repository" | jq -r .repositoryId)

  echo "${id}=${name}"
done < <(echo "$repositories" | jq -c '.repositories[]')