这是一个查询模式，我在很多年前就找到了答案：

SELECT *
FROM mytable a
JOIN mytable b on a.starttime <= b.endtime
    and a.endtime >= b.starttime
    and a.name != b.name; -- ideally, this would compare a "key" column, eg id

为了找到“任何重叠”，您将时间框架的“相反”两端相互比较。这是我不得不拿出笔和纸，并绘制相邻的范围，以实现边缘情况归结为这种比较。
如果要防止任何行重叠，请将此查询的变体放入触发器中：

create trigger mytable_no_overlap
before insert on mytable
for each row
begin
  if exists (select * from mytable
             where starttime <= new.endtime
             and endtime >= new.starttime) then
    signal sqlstate '45000' SET MESSAGE_TEXT = 'Overlaps with existing data';
  end if;
end;

我想要一个通用函数来检查两个时间范围是否重叠，这也适用于计划在午夜之前开始并在午夜之后结束的情况，例如“17：00：00-03：00：00”和“14：00：00-01：00：00”应该重叠，所以我修改了solution by Bohemian
您可以按如下方式使用此函数

SELECT func_time_overlap("17:00:00","03:00:00", "14:00:00","01:00:00")

或者像你这样

SELECT *
FROM mytable a
JOIN mytable b ON (
    a.name != b.name 
    AND func_time_overlap(a.starttime, a.endtime, b.starttime, b.endtime)
);

下面是函数定义

CREATE FUNCTION `func_time_overlap`(a_start TIME, a_end TIME, b_start TIME, b_end TIME) 
RETURNS tinyint(1) 
DETERMINISTIC
BEGIN

-- there are only two cases when they don't overlap, but a lot of possible cases where they do overlap

-- There are two time formats, one is an interval of time that can go over 24 hours, the other is a daily time format that never goes above 24 hours
-- by default mysql uses TIME as an interval
-- this converts a TIME interval into a date time format

-- I'm not using `TIME(CAST(a_start AS DATETIME));` to convert the time interval to a time
-- because it uses the current day by default and might get affected by the timezone settings of the database, 
-- just imagine the next day having the DST change.
-- although the CAST should work fine if you use UTC

IF a_start >= 24 THEN 
    SET a_start = TIME(CONCAT(MOD(HOUR(a_start), 24),':',MINUTE(a_start),':',SECOND(a_start))); 
END IF;

IF b_start >= 24 THEN 
    SET b_start = TIME(CONCAT(MOD(HOUR(b_start), 24),':',MINUTE(b_start),':',SECOND(b_start))); 
END IF;

IF a_end > 24 THEN 
    SET a_end = TIME(CONCAT(MOD(HOUR(a_end), 24),':',MINUTE(a_end),':',SECOND(a_end))); 
END IF;

IF b_end > 24 THEN 
    SET b_end = TIME(CONCAT(MOD(HOUR(b_end), 24),':',MINUTE(b_end),':',SECOND(b_end))); 
END IF;

-- if the time range passes the midnight mark, then add 24 hours to the time
IF a_start >= a_end THEN 
    SET a_end = a_end + INTERVAL 24 HOUR; 
END IF;

IF b_start >= b_end THEN 
    SET b_end = b_end + INTERVAL 24 HOUR; 
END IF;

RETURN a_start < b_end AND a_end > b_start;

END

我没有使用TIME(CAST(a_start AS DATETIME));将时间间隔转换为时间，因为它默认使用当前日期，可能会受到数据库时区设置的影响，想象一下第二天DST发生变化。
如果您的数据库使用的是UTC时区（应该如此），则可以使用此

IF a_start >= 24 THEN 
    SET a_start = TIME(CAST(a_start AS DATETIME)); 
END IF;

IF b_start >= 24 THEN 
    SET b_start = TIME(CAST(b_start AS DATETIME)); 
END IF;

IF a_end > 24 THEN 
    SET a_end = TIME(CAST(a_end AS DATETIME));
END IF;

IF b_end > 24 THEN 
    SET b_end = TIME(CAST(b_end AS DATETIME));
END IF;

试试这个：

declare @tempTbl table(RecID)

    insert into @tempTbl
    Select RecID
    from 
    (
    Select t.RecID from Table1 t,Table1 t1
    where t.StartTime between t1.StartTime AND t1.EndTime
    AND t.RecID <> t1.RecID  

    )

试试这个，对我有用

SELECT * from Shedulles a 
where exists 
( select 1 from Shedulles b 
    where 
    a.ShedulleId != b.ShedulleId 
    and ( a.DateFrom between b.DateFrom and b.DateTo 
    or a.DateTo between b.DateFrom and b.DateTo 
    or b.DateFrom between a.DateFrom and a.DateTo ) 
    and a.DateFrom != b.DateTo 
    and b.DateFrom != a.DateTo 
);

或者这一个

SELECT DISTINCT a.* FROM Shedulles a
JOIN Shedulles b 
    ON 
    a.ShedulleId != b.ShedulleId 
    and ( a.DateFrom between b.DateFrom and b.DateTo 
    or a.DateTo between b.DateFrom and b.DateTo 
    or b.DateFrom between a.DateFrom and a.DateTo ) 
    and a.DateFrom != b.DateTo 
    and b.DateFrom != a.DateTo

在PHP中很简单。按开始时间对列表进行排序，然后检查 * 连续 * 条目是否重叠：

$end[$k] > $start[$k+1]

MySQL中的等效方法更复杂，除非您使用MySQL 8.0（或MariaDB 10.2），因为需要LEAD()或LAG()来查看相邻行。