这应该非常简单-我需要从函数返回一个哈希表数组。当有多个哈希表时,这是有效的,但是当只有一个哈希表时,结果不是数组。我宁愿不测试结果是否是数组。
function GetArrayWith1Hashtable()
{
$array = @()
$hashtable = @{}
$hashtable["a"] = "a"
$hashtable["b"] = "b"
$hashtable["c"] = "c"
$array += $hashtable
Write-Host "GetArrayWith1Hashtable array.Length =" $array.Length
Write-Host "GetArrayWith1Hashtable array.Count" $array.Count
Write-Host "GetArrayWith1Hashtable array[0].Keys" $array[0].Keys
$array
}
function GetArrayWith2Hashtables()
{
$array = @()
$hashtable = @{}
$hashtable["a"] = "a"
$hashtable["b"] = "b"
$hashtable["c"] = "c"
$array += $hashtable
$hashtable2 = @{}
$hashtable2["d"] = "d"
$hashtable2["e"] = "e"
$hashtable2["f"] = "f"
$array += $hashtable2
Write-Host "GetArrayWith2Hashtables array.Length = " $array.Length
Write-Host "GetArrayWith2Hashtables array.Count = " $array.Count
Write-Host "GetArrayWith2Hashtables array[0].Keys =" $array[0].Keys
Write-Host "GetArrayWith2Hashtables array.Count = "$array[1].Keys
$array
}
$result1 = GetArrayWith1Hashtable
# $result1.Length - not available
Write-Host "Result of GetArrayWith1Hashtable result1.Count = " $result1.Count # Count = 2 (would expect this to be 1)
# $result1[0] not available - not an array
$result2 = GetArrayWith2Hashtables
Write-Host "Result of GetArrayWith2Hashtables result2.Length = " $result2.Length # Length = 2
Write-Host "Result of GetArrayWith2Hashtables result2.Count = " $result2.Count # Count = 2
Write-Host "Result of GetArrayWith2Hashtables result2[0].Keys = " $result2[0].Keys # Keys = c a b
Write-Host "Result of GetArrayWith2Hashtables result2[1].Keys = " $result2[1].Keys # Keys = d e f
<#
FULL OUTPUT:
GetArrayWith1Hashtable array.Length = 1
GetArrayWith1Hashtable array.Count 1
GetArrayWith1Hashtable array[0].Keys c a b
Result of GetArrayWith1Hashtable result1.Count = 2
GetArrayWith2Hashtables array.Length = 2
GetArrayWith2Hashtables array.Count = 2
GetArrayWith2Hashtables array[0].Keys = c a b
GetArrayWith2Hashtables array.Count = d e f
Result of GetArrayWith2Hashtables result2.Length = 2
Result of GetArrayWith2Hashtables result2.Count = 2
Result of GetArrayWith2Hashtables result2[0].Keys = c a b
Result of GetArrayWith2Hashtables result2[1].Keys = d e f
#>
3条答案
按热度按时间qeeaahzv1#
实际上,你只需要在返回的项目前面加一个逗号就可以了。这告诉PowerShell按原样返回它,而不试图聪明地处理它。这也允许您在一个地方修复它,而不是在所有调用它的地方。
**更新:**虽然,我不认为你想要这个功能,但我会提到它,以便其他人能够理解其中的区别,并为他们的方法做出明智的选择。
为了让你的函数兼容,以便在管道中更有效地使用,更好的方法是为每个项调用Write-Output。
通过使用Write-Output,您允许PowerShell在管道中为每个对象单独调用下一个命令的Process block。否则,它将调用下一个命令并向其传递单个数组对象。您可以在此处阅读更多有关管道对象的信息
7hiiyaii2#
将返回类型转换为数组:
icnyk63a3#
为了强制函数返回一个数组(不管集合的大小),我这样做:
我认为-NoEnumerate开关有助于使我想要做的事情更加明确。