使用fasm编写一个x86汇编程序，将用户输入的整数（从-100到100）转换为文本。
下面是我推荐的一个算法：
1.要求用户输入数字并存储到[Num]中
1.如果number小于0，输出“negative”并将其更改为正数
1.打印所有异常-检查编号是否为100、0、10、11、12、13、14、15、16、17、18、19。如果是，输出数字并结束
1.将数字除以10，并将答案存储为[商]和[余数]
1.将Quotient与20，30，40，50，60，70，80，90进行比较，并输出十位数-例如“二十”
1.将余数与1、2、3、4、5、6、7、8、9进行比较，并输出一位数-例如“五”
1.跳转到开始重复整个程序
示例输出此x86汇编程序将整数转换为文本。
输入一个介于-100到100之间的整数：73
七十三
输入一个介于-100到100之间的整数：-100
负一百
有人能帮我这个程序吗
我的意思是我写了程序，但完全不能得到预期的输出

format PE console
entry start

include 'win32ax.inc'

section '.data' data readable writable
    Num dd ?
    negative db "negative ", 0
    exceptions db "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen", 0
    tens db "", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety", 0
    output_msg db "%s", 0
    intro_msg db "This x86 assembly program converts an integer to text.", 0
    input_msg db "Enter an integer from -100 to 100: ", 0

section '.code' code readable executable
start:
    cinvoke printf, intro_msg
    cinvoke printf, input_msg
    cinvoke scanf, "%d", Num     ; Read user input
    
    mov eax, [Num]
    cmp eax, 0
    jge check_exceptions
    
    ; Output "negative " and change to positive
    cinvoke printf, negative
    neg eax
    mov [Num], eax

check_exceptions:
    cmp eax, 100
    je output_result
    
    cmp eax, 0
    je output_exception
    
    cmp eax, 10
    jl divide_by_10
    
    cmp eax, 20
    jl output_tens
    
    mov edx, eax
    shr eax, 1
    shl edx, 31
    sar eax, 31
    xor edx, eax
    sub edx, eax
    movzx eax, dx
    
    lea edx, [exceptions + eax * 4]
    cinvoke printf, output_msg, edx
    
    jmp restart

divide_by_10:
    ; Divide by 10 to get tens and ones digits
    mov ebx, 10
    xor edx, edx
    div ebx
    movzx ecx, dl    ; Remainder is ones digit
    movzx ebx, al    ; Quotient is tens digit
    
    cmp ebx, 0
    je output_ones
    
    ; Output tens digit if not zero
    lea edx, [tens + ebx * 4]
    cinvoke printf, output_msg, edx
    
output_ones:
    cmp ecx, 0
    je restart
    
    ; Output ones digit
    lea edx, [exceptions + ecx * 4]
    cinvoke printf, output_msg, edx
    
    jmp restart

output_tens:
    sub eax, 10
    lea edx, [tens + eax * 4]
    cinvoke printf, output_msg, edx
    
    jmp restart

output_exception:
    lea edx, [exceptions + eax * 4]
    cinvoke printf, output_msg, edx

output_result:
    ; Output the number as text
    lea edx, [exceptions + eax * 4]
    cinvoke printf, output_msg, edx

restart:
    jmp start

section '.idata' import data readable
    library msvcrt, 'msvcrt.dll'
    import msvcrt, printf, 'printf', scanf, 'scanf', ExitProcess, 'ExitProcess'

so after this when i run the program and give the input as 5 the output is something else. please if anyone could help me fix this issue.i would really appreciate it.