没有这样的等价物，但您可以在创建连接之前修补较低级别以重写远程地址。
这在Python 3中是可行的：

from unittest.mock import patch

# contextmanager for forcing a connection to a given host, port
def connect_to(host, port):
    from urllib3.util.connection import create_connection as orig_create_connection
                                                                                
    def _forced_address_connection(address, *args, **kwargs):
        forced_address = (host, port)
        return orig_create_connection(forced_address, *args, **kwargs)

    return patch('urllib3.util.connection.create_connection', _forced_address_connection)

# force connections to 127.0.0.1:8080
with connect_to('127.0.0.1', 8080):
    res = requests.get('http://service.example.com/')

像修补PoolManager或使用自定义适配器这样的解决方案是不够的，因为URL也会被重写（因此Host:头也会被重写）。当你使用curl --connect-to时，在HTTP级别没有任何改变。
我还需要选择性地强制http连接，尽管有URL方案。这是它的工作增强版本：

import contextlib
from unittest.mock import patch

@contextlib.contextmanager
def connect_to(host, port, force_http=False):
    from urllib3.connection import HTTPConnection
    from urllib3.util.connection import create_connection as orig_create_connection

    def _forced_address_connection(address, *args, **kwargs):
        forced_address = (host, port)
        return orig_create_connection(forced_address, *args, **kwargs)

    class ForcedHTTPConnection(HTTPConnection):
        def __init__(self, **kwargs):
            httpconn_kw = ('host', 'port', 'timeout', 'source_address', 'blocksize')
            httpconn_kwargs = dict([(k, kwargs[k]) for k in httpconn_kw if k in kwargs])
            super().__init__(**httpconn_kwargs)

    patchers = [patch('urllib3.util.connection.create_connection', _forced_address_connection)]
    if force_http:
        patchers.append(patch('urllib3.connectionpool.HTTPSConnectionPool.ConnectionCls', ForcedHTTPConnection))

    for p in patchers:
        p.start()

    yield

    for p in patchers:
        p.stop()

# force connections to 127.0.0.1:8080 using http
with connect_to('127.0.0.1', 8080, force_http=True):
    res = requests.get('https://service.example.com/')

参见Python 'requests' library - define specific DNS?。