Mongoose Populate的严格类型化

l2osamch 于 2023-06-30 发布在 Go

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是否有任何方法来定义/修改接口或类型，以 * Assert * 文档将使用mongoose填充到typescript中？
例如

interface ISchool {
   name: string;
   address; string;
}
interface IPerson {
   name: string;
   school?: PopulatedDoc<ISchool & Document>
}
const PersonSchema: Schema<IPerson> = new Schema<IPerson>({
    name: { type: String },
    school: { type: Schema.Types.ObjectId, ref: 'School' }
})
const Person = mongoose.model<IPerson>('Person', PersonSchema);
export default Person

然后，本质上，如果我们与Person文档交互，就没有办法知道school属性是否被填充。例如。

const person = await Person.findOne({});
if (person.school) { . . . } // is `school` an ObjectId or a Document?

和

const person = await Person.findOne({}, undefined, { populate: { path: 'school', model: 'School'} });
if (person.school) { . . . } // is `school` an ObjectId or a Document?

是否有任何方法可以Assert文档属性已被填充？
谢谢

mongoose

来源：https://stackoverflow.com/questions/76576520/strict-typing-for-mongoose-populate

1条答案

按热度按时间

xiozqbni1#

从populate-with-typescript文档中，我们可以：
将泛型参数Paths添加到populate()

import mongoose, { Types } from 'mongoose';

interface ISchool {
    name: string;
    address: string;
}
interface IPerson {
    name: string;
    school?: Types.ObjectId;
}
const PersonSchema: mongoose.Schema<IPerson> = new mongoose.Schema<IPerson>({
    name: { type: String },
    school: { type: mongoose.Schema.Types.ObjectId, ref: 'School' },
});

const Person = mongoose.model<IPerson>('Person', PersonSchema);

(async function run() {
    const person1 = await Person.findOne({});
    person1?.school; // school is ObjectId

    const person2 = await Person.findOne({}).populate<{ school: ISchool }>({ path: 'school', model: 'School' });
    person2?.school; // scholl is ISchool
})();

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Mongoose Populate的严格类型化

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