.net 有没有可能使WinForms Tab控件能够像IE或Firefox一样进行标签重新排序?

f4t66c6m  于 2023-07-01  发布在  .NET
关注(0)|答案(5)|浏览(91)

是否可以像IE或Firefox一样在运行时对WinForms TabControl中的选项卡进行重新排序?
Links like this不要给予我太多希望。

tf7tbtn2

tf7tbtn21#

通过拖放重新排序TabPages- * 作者:Ludwig B.*

灵感来自http://dotnetrix.co.uk/tabcontrol.htm#tip7

private void tc_MouseDown(object sender, MouseEventArgs e)
        {
            // store clicked tab
            TabControl tc = (TabControl)sender;
            int hover_index = this.getHoverTabIndex(tc);
            if (hover_index >= 0) { tc.Tag = tc.TabPages[hover_index]; }
        }
        private void tc_MouseUp(object sender, MouseEventArgs e)
        {
            // clear stored tab
            TabControl tc = (TabControl)sender;
            tc.Tag = null;
        }
        private void tc_MouseMove(object sender, MouseEventArgs e)
        {           
            // mouse button down? tab was clicked?
            TabControl tc = (TabControl)sender;
            if ((e.Button != MouseButtons.Left) || (tc.Tag == null)) return;
            TabPage clickedTab = (TabPage)tc.Tag;
            int clicked_index = tc.TabPages.IndexOf(clickedTab);

            // start drag n drop
            tc.DoDragDrop(clickedTab, DragDropEffects.All);
        }
        private void tc_DragOver(object sender, DragEventArgs e)
        {
            TabControl tc = (TabControl)sender;

            // a tab is draged?
            if (e.Data.GetData(typeof(TabPage)) == null) return;
            TabPage dragTab = (TabPage)e.Data.GetData(typeof(TabPage));
            int dragTab_index = tc.TabPages.IndexOf(dragTab);

            // hover over a tab?
            int hoverTab_index = this.getHoverTabIndex(tc);
            if (hoverTab_index < 0) { e.Effect = DragDropEffects.None; return; }
            TabPage hoverTab = tc.TabPages[hoverTab_index];
            e.Effect = DragDropEffects.Move;

            // start of drag?
            if (dragTab == hoverTab) return;

            // swap dragTab & hoverTab - avoids toggeling
            Rectangle dragTabRect = tc.GetTabRect(dragTab_index);
            Rectangle hoverTabRect = tc.GetTabRect(hoverTab_index);

            if (dragTabRect.Width < hoverTabRect.Width)
            {
                Point tcLocation = tc.PointToScreen(tc.Location);

                if (dragTab_index < hoverTab_index)
                {
                    if ((e.X - tcLocation.X) > ((hoverTabRect.X + hoverTabRect.Width) - dragTabRect.Width))
                        this.swapTabPages(tc, dragTab, hoverTab);
                }
                else if (dragTab_index > hoverTab_index)
                {
                    if ((e.X - tcLocation.X) < (hoverTabRect.X + dragTabRect.Width))
                        this.swapTabPages(tc, dragTab, hoverTab);
                }
            }
            else this.swapTabPages(tc, dragTab, hoverTab);

            // select new pos of dragTab
            tc.SelectedIndex = tc.TabPages.IndexOf(dragTab);
        }

        private int getHoverTabIndex(TabControl tc)
        {
            for (int i = 0; i < tc.TabPages.Count; i++)
            {
                if (tc.GetTabRect(i).Contains(tc.PointToClient(Cursor.Position)))
                    return i;
            }

            return -1;
        }

        private void swapTabPages(TabControl tc, TabPage src, TabPage dst)
        {
            int index_src = tc.TabPages.IndexOf(src);
            int index_dst = tc.TabPages.IndexOf(dst);
            tc.TabPages[index_dst] = src;
            tc.TabPages[index_src] = dst;
            tc.Refresh();
        }
blpfk2vs

blpfk2vs2#

我把雅各布·斯坦利的回答延伸了一点。这样交换就不会太频繁。这对于不同大小的选项卡特别有用,在这种情况下,以前的解决方案在拖动时会经常交换。
用户体验的不同之处在于,您必须再拖动一点才能实际移动选项卡。但这类似于浏览器中的标签重新排序。
此外,我添加了一个手光标,而拖动和启用双缓冲。

using System;
using System.Drawing;
using System.Windows.Forms;

namespace Controls
{
    public class DraggableTabControl : TabControl
    {
        private TabPage draggedTab;

        public DraggableTabControl()
        {
            this.MouseDown += OnMouseDown;
            this.MouseMove += OnMouseMove;
            this.Leave += new System.EventHandler(this.DraggableTabControl_Leave);

            this.SetStyle(ControlStyles.OptimizedDoubleBuffer | ControlStyles.AllPaintingInWmPaint, true);
        }

        private void OnMouseDown(object sender, MouseEventArgs e)
        {
            draggedTab = TabAt(e.Location);
        }

        private void OnMouseMove(object sender, MouseEventArgs e)
        {
            if (e.Button != MouseButtons.Left || draggedTab == null)
            {
                this.Cursor = this.DefaultCursor;
                draggedTab = null;
                return;
            }

            int index = TabPages.IndexOf(draggedTab);          
            int nextIndex = index + 1;
            int prevIndex = index - 1;

            int minXForNext = int.MaxValue;
            int maxXForPrev = int.MinValue;

            var tabRect = GetTabRect(index);

            if (nextIndex < TabPages.Count)
            {
                var nextTabRect = GetTabRect(nextIndex);
                minXForNext = tabRect.Left + nextTabRect.Width;
            }

            if (prevIndex >= 0)
            {
                var prevTabRect = GetTabRect(prevIndex);
                maxXForPrev = prevTabRect.Left + tabRect.Width;
            }

            this.Cursor = Cursors.Hand;

            if (e.Location.X > maxXForPrev && e.Location.X < minXForNext)
            {
                return;
            }

            TabPage tab = TabAt(e.Location);

            if (tab == null || tab == draggedTab)
            {
                return;
            }

            Swap(draggedTab, tab);
            SelectedTab = draggedTab;
        }

        private TabPage TabAt(Point position)
        {
            int count = TabCount;

            for (int i = 0; i < count; i++)
            {
                if (GetTabRect(i).Contains(position))
                {
                    return TabPages[i];
                }
            }

            return null;
        }

        private void Swap(TabPage a, TabPage b)
        {
            int i = TabPages.IndexOf(a);
            int j = TabPages.IndexOf(b);

            TabPages[i] = b;
            TabPages[j] = a;
        }

        private void DraggableTabControl_Leave(object sender, EventArgs e)
        {
            this.Cursor = this.DefaultCursor;
            draggedTab = null;
        }
    }
}
2cmtqfgy

2cmtqfgy3#

这是一个非常古老的问题,但如果有人要使用它。功能中建议的解决方案存在问题,该功能会交换选项卡。TabPages和Controls集合不同步,交换后TabPages.RemoveAt的行为将不正确。以下是修改它的方法:

tc.TabPages[index_src] = dst;
    tc.Controls.SetChildIndex(tc.Controls[index_src], index_dst);
    tc.Refresh();
c6ubokkw

c6ubokkw4#

**当然,这是可能的!**你很可能试图把解决方案复杂化。本质上,您所要做的就是继承标准TabControl并向鼠标事件处理程序添加一些逻辑。您只需要检查用户当前正在拖动的表单,并在TabPages集合中对其进行重新排序。

在线提供了几个完整的解决方案:

xe55xuns

xe55xuns5#

我发现最初由@Cody Gray发布的解决方案主要是我想要的,但我不认为它需要如此复杂。
这是我的简化,通过从TabControl派生实现:

public class DraggableTabControl : TabControl
{
    private TabPage m_DraggedTab;

    public DraggableTabControl()
    {
        MouseDown += OnMouseDown;
        MouseMove += OnMouseMove;
    }

    private void OnMouseDown(object sender, MouseEventArgs e)
    {
        m_DraggedTab = TabAt(e.Location);
    }

    private void OnMouseMove(object sender, MouseEventArgs e)
    {
        if (e.Button != MouseButtons.Left || m_DraggedTab == null)
        {
            return;
        }

        TabPage tab = TabAt(e.Location);

        if (tab == null || tab == m_DraggedTab)
        {
            return;
        }

        Swap(m_DraggedTab, tab);
        SelectedTab = m_DraggedTab;
    }

    private TabPage TabAt(Point position)
    {
        int count = TabCount;

        for (int i = 0; i < count; i++)
        {
            if (GetTabRect(i).Contains(position))
            {
                return TabPages[i];
            }
        }

        return null;
    }

    private void Swap(TabPage a, TabPage b)
    {
        int i = TabPages.IndexOf(a);
        int j = TabPages.IndexOf(b);
        TabPages[i] = b;
        TabPages[j] = a;
    }
}

拖放API实际上是用于在独立的应用程序之间拖动内容,或者至少是在独立的控件之间拖动内容。在这种情况下使用它们是过度的。
如果你赞成我的答案,一定要赞成科迪的答案,因为它是基于他的。

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