类似下面的东西

my_objects = [
    {
        "id": 0,
        "some_value": "a"
    },
    {
        "id": 1,
        "some_value": "a"
    },
    {
        "id": 2,
        "some_value": "b"
    },
    {
        "id": 3,
        "some_value": "b"
    },
]
ids = [1, 2]
final_list = [x['some_value'] for x in my_objects if x['id'] in ids]
print(final_list)

输出

['a', 'b']

有一个简洁的可选if部件列表解析：

[obj["some_value"] for obj in my_objects if obj["id"] in ids]

ids = [x.get("some_value") for x in my_objects if x['id'] in ids]

#print(ids)
['a', 'b']

你可以尝试这样的东西：

my_objects = [
    {
        "id":0,
        "some_value":"a"
    },
    {
        "id":1,
        "some_value":"a"
    },
    {
        "id":2,
        "some_value":"b"
    },
    {
        "id":3,
        "some_value":"b"
    },
]
id_to_select = [1 ,2]
my_objects_filtered = [obj["some_value"] for obj in my_objects if obj["id"] in id_to_select]
print(my_objects_filtered) 
# [{'id': 1, 'some_value': 'a'}, {'id': 2, 'some_value': 'b'}]

但我不确定是不是pythonic的方式
使用filter和lambda可能更好：

my_objects = [
    {
        "id":0,
        "some_value":"a"
    },
    {
        "id":1,
        "some_value":"a"
    },
    {
        "id":2,
        "some_value":"b"
    },
    {
        "id":3,
        "some_value":"b"
    },
]
id_to_select = [1 ,2]
my_objects_filtered = list(map(lambda obj: obj["some_value"],filter(lambda obj: obj["id"] in id_to_select, my_objects)))
print(my_objects_filtered)
# ['a', 'b']

如果你知道id和some_value会出现在每个字典中，那么你可以使用operator.itemgetter：

from operator import itemgetter

get_id_val = itemgetter("id", "some_value")

result = [val for i, val in map(get_id_val, my_objects) if i in ids]

如果你也知道它们是有序的，并且字典只有2个键，那么你可以只Mapdict.values：

[val for i, val in map(dict.values, my_objects) if i in ids]

如果它们是有序的，但可能有更多的键，那么只需抛出一个catch all变量：

[val for i, val, *_ in map(dict.values, my_objects) if i in ids]