将数据传递回前一个视图控制器的最好方法是通过委托。。当从ViewController A转到B时，将视图控制器A作为委托传递，并在ViewController B的viewWillDisappear方法上，调用ViewController A中的委托方法。协议将帮助定义委托和需要由以前的VC实现的方法。这里有一个简单的例子：
传递数据的协议：

protocol isAbleToReceiveData {
  func pass(data: String)  //data: string is an example parameter
}

视图控制器A：

class viewControllerA: UIViewController, isAbleToReceiveData {

  func pass(data: String) { //conforms to protocol
  // implement your own implementation
   }

  prepare(for: Segue) {
    /** code for passing data **/
    let vc2 = ViewCOntrollerB()  /
    vc2.delegate = self   //sets the delegate in the new viewcontroller 
                          //before displaying
    present(vc2)
  }
}

正在解除viewcontroller：

class viewControllerB: UIViewController {

  var delegate: isAbleToReceiveData

  viewWillDisappear {
      delegate.pass(data: "someData") //call the func in the previous vc
  }
}

在解除完成块中，创建EditViewController的新示例。我假设导航堆栈中存在另一个EditViewController示例，您需要找到该示例并将segueArray设置为values。你可以通过遍历你的导航堆栈的viewcontrollers来实现，比如：

viewController.navigationController?.viewControllers.forEach({ (vc) in
    if let editVC = vc as? EditViewController {
        editVC.segueArray = ....
    }
})

但我建议使用delegate模式，比如：

protocol EditViewControllerDelegate: class {
    func setSegueArray(segues: [UIStoryboardSegue])
}

在dismiss块所在的viewcontroller（称之为ViewController）中，声明一个delegate属性：

class ViewController: UIViewController {
    weak var delegate: EditViewControllerDelegate?
    ....
}

然后，在呈现（我假设来自EditViewController）ViewController的示例时，设置委托如下：

...
if let vc = presentingViewController as? ViewController {
    vc.delegate = self
}

并使EditViewController符合委托协议，如：

extension EditViewController: EditViewControllerDelegate {
    func setSegueArray(segues: [UIStoryboardSegue]) {
        // Do the data setting here eg. self.segues = segues
    }
}

要检测何时按下视图控制器上的后退按钮，我只需用途：

override func didMove(toParentViewController parent: UIViewController?) {
    guard parent == nil else { return } // Back button pressed

    ... // Pass on the info as shown in you example
} // didMoveToParentViewController

通用解决方案：（🔸Swift 5.1）

/**
 * Returns a ViewController of a class Kind
 * ## Examples:
 * UIView.vc(vcKind: CustomViewController.self) // ref to an instance of CustomViewController
 */
public static func vc<T: UIViewController>(vcKind: T.Type? = nil) -> T? {
   guard let appDelegate = UIApplication.shared.delegate, let window = appDelegate.window else { return nil }
   if let vc = window?.rootViewController as? T {
      return vc
   } else if let vc = window?.rootViewController?.presentedViewController as? T {
      return vc
   } else if let vc = window?.rootViewController?.children {
      return vc.lazy.compactMap { $0 as? T }.first
   }
   return nil
}

我认为最简单的解决方案是使用完成处理程序：
示例：

class EditViewController {
    let secondController = SecondController()
    
    func showSecondController() {
        secondController.show() { data in
            //
        }
    }
}

class SecondController {
    var completion: ((_ data: Any?) -> Void)?
    
    func show(completion: @escaping (_ data: Any?) -> Void) {
        // Show something
        self.completion = completion
    }

    func dismiss() {
        if let completion = self.completion {
            completion(nil)
        }
    }
}