我有一个列表,看起来像这样:
['192.168.0.1 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:42','10.60.37.2 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:41','192.168.0.240 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:40']
字符串
当我导出到Excel,每个块是在一个不同的行,这是好的,但都在同一列,我想有地址列1开关列2等
Excel column 1
Excel row1: 192.168.0.1 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:42
Excel row2: 10.60.37.2 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:41
Excel row3 :192.168.0.240 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:40
型
我想要这样
exlcol1 exlcol2 exl.col3 exl.col4 exl.col5 exl.col6
exlrow1: 192.168.0.1 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:42
exlrow2: 10.60.37.2 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:41
exlrow3 :192.168.0.240 switch1 ff:ff:ff:ff:ff:ff 657 dynamic port:40
型
我试着将它导出到csv,但它说wtr.writerows(row)
必须是byte.object
,然后我试图将我的列表更改为字符串,将其更改为byte.object,但它说我的wtr.writerows(row)
应该是可输入的。
下面是我用来导出到csv的代码
import csv
with open('test.csv', 'wb') as f:
wtr = csv.writer(f, delimiter= ',')
for row in data11parts1:
wtr.writerows(row)
with open('test.csv', 'r') as f:
for line in f:
print (line)
型
我的偏好是将其导出到Excel,但我认为这可以帮助您更好地解释我的问题和我拥有的数据类型。
我只是想告诉你,我的数据11部分1来自这个附件:
for element in data2:
elementstring=''.join(element)
for element in res1:
elementstring5=''.join(element)
if elementstring in elementstring5:
with open(Sw1, 'r') as f3:
for line5 in f3:
if elementstring in line5:
print('managemnet-tool' + ' - ' + Sw1.rsplit('.txt',1)[0] + ' - ' + elementstring5.rsplit('-', 1)[0] + ' - ' + line5.rsplit('\n', 1)[0])
data11.append(elementstring5.rsplit('-',1)[0] + ' ' + Sw1.rsplit('.txt',1)[0] + ' ' + line5.rsplit('\n', 1)[0])
data13.append(str(line5.rsplit('\n', 1)[0]))
exit
型
1条答案
按热度按时间lymgl2op1#
它会抱怨,因为你打开文件进行二进制写入。写CSV很简单,将内部字符串拆分成列表(以空格分隔)并编写它们:
字符串
文件内容:
型
请参阅