创建pandas dataframe的新列：

jjhzyzn0 于 2023-08-01 发布在其他

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我有一个pandas数据框架，名为cica_df：

Fecha     |Administradora_descrip|Fondo_descrip|PUC_Codigo|PUC_Descrip|Saldo_Cuenta|CRNCY|
--------------------------------------------------------------------------------------------
2007-01-31|Colfondos               |Largo Plazo  |100000  |ACTIVO     |4.517769e+11|COP  |
2007-01-31|Colfondos               |Largo Plazo  |162800  |DEPOSITO   |6.386133e+12|COP  |
2007-01-31|Skandia                 |Largo Plazo  |100000  |ACTIVO     |3.517769e+11|COP  |
2007-01-31|Skandia                 |Largo Plazo  |162800  |DEPOSITO   |7.386133e+12|COP  |
2007-02-28|Colfondos               |Largo Plazo  |100000  |ACTIVO     |4.897769e+11|COP  |
2007-02-28|Colfondos               |Largo Plazo  |162800  |DEPOSITO   |6.986133e+12|COP  |
2007-02-28|Skandia                 |Largo Plazo  |100000  |ACTIVO     |4.907769e+11|COP  |
2007-02-28|Skandia                 |Largo Plazo  |162800  |DEPOSITO   |6.766133e+12|COP  |

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我需要创建一个新列我需要创建一个新列，其值是列“Account_Balance”的值，这样在列“PUC_Code”中，对于列中所有列的值都是100000，在列日期，Admin_descripp，基金_descripp和CRNCY中具有相同值。所以我可以得到一个pandas dataframe，如下所示：

Fecha     |Administradora_descrip|Fondo_descrip|PUC_Codigo|PUC_Descrip|Saldo_Cuenta|CRNCY|Nav        |
-------------------------------------------------------------------------------------------------------
2007-01-31|Colfondos               |Largo Plazo  |100000  |ACTIVO     |4.517769e+11|COP|4.517769e+11 |
2007-01-31|Colfondos               |Largo Plazo  |162800  |DEPOSITO   |6.386133e+12|COP|4.517769e+11 |
2007-01-31|Skandia                 |Largo Plazo  |100000  |ACTIVO     |3.517769e+11|COP|3.517769e+11 |
2007-01-31|Skandia                 |Largo Plazo  |162800  |DEPOSITO   |7.386133e+12|COP|3.517769e+11 |
2007-02-28|Colfondos               |Largo Plazo  |100000  |ACTIVO     |4.897769e+11|COP|4.897769e+11 |
2007-02-28|Colfondos               |Largo Plazo  |162800  |DEPOSITO   |6.986133e+12|COP|4.897769e+11 |
2007-02-28|Skandia                 |Largo Plazo  |100000  |ACTIVO     |4.907769e+11|COP|4.907769e+11 |
2007-02-28|Skandia                 |Largo Plazo  |162800  |DEPOSITO   |6.766133e+12|COP|4.907769e+11 |

型
我试过这个代码：

cica_df['Nav'] = np.where(cica_df['PUC_Codigo'] == 100000, cica_df['Saldo_Cuenta'], cica_df['Saldo_Cuenta'])

型
但它只重复了列“Saldo_Cuenta”。我该怎么办？

pandas

来源：https://stackoverflow.com/questions/76766300/creating-a-new-column-of-a-pandas-dataframe

1条答案

按热度按时间

pb3skfrl1#

您可以使用pandas中的groupby函数来实现这一点

import pandas as pd

# Group by the specified columns and calculate the account balance for PUC_Code == 100000
cica_df['Nav'] = cica_df.groupby(['Fecha', 'Administradora_descrip', 'Fondo_descrip', 'CRNCY'])['Saldo_Cuenta'].transform(
    lambda x: x.loc[x['PUC_Codigo'] == 100000].iloc[0])

print(cica_df)

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创建pandas dataframe的新列：

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