下面是等效的Node.js正则表达式

/\bhttps?:\/\/[^,\s()<>]+(?:\([\w\d]+\)|([^,\p{P}\s]|\/))/gu

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演示和说明：https://regex101.com/r/Y2vlwe/1

const regex = /\bhttps?:\/\/[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|\/))/g;
const script = "Your input here";

const matches = script.match(regex);
console.log(matches);

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const regex = /\bhttps?:\/\/[^,\s()<>]+(?:\([\w\d]+\)|([^,\p{P}\s]|\/))/gu;
const v = "https://www.google.com";
const v1 = "sampel text";

const matches = v.match(regex);   // matches
const matches1 = v1.match(regex); // Not matches
console.log(matches);
console.log(matches1);

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我假设你正在尝试检查一个有效的URL。JavaScript中最简单的事情就是这样做：

let url = 'https://gooogle.com';

  try {
   const parts = new URL(url);
   console.log(parts);

  } catch(err) {
     console.error('not a valid url', err);
  }

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