ruby Rails数据库系统：`initialize '：无此表：一个表列出现main.dinners(SQLite3：：SQLException)错误，但其他列没有

a7qyws3x 于 2023-08-04 发布在 Ruby

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我有一个简单的rails 7应用程序，我可以在其中创建一个每周菜单。然后，用户可以选择他们想要的星期几。
我在设计和制作上遇到了点麻烦。这是我到目前为止所拥有的：

rails generate model WeeklyMenu monday:references tuesday:references wednesday:references thursday:references friday:references saturday:references sunday:references
rails generate model Day lunch:references brunch:references dinner:references
rails generate model Meal title:string description:text

字符串
第一个月

class WeeklyMenu < ApplicationRecord
  belongs_to :monday, class_name: 'Day'
  belongs_to :tuesday, class_name: 'Day'
  belongs_to :wednesday, class_name: 'Day'
  belongs_to :thursday, class_name: 'Day'
  belongs_to :friday, class_name: 'Day'
  belongs_to :saturday, class_name: 'Day'
  belongs_to :sunday, class_name: 'Day'
end

型
app/models/day.rb个

class Day < ApplicationRecord
  belongs_to :lunch, class_name: 'Meal'
  belongs_to :brunch, class_name: 'Meal'
  belongs_to :dinner, class_name: 'Meal'
end

型
app/models/meal.rb个

class Meal < ApplicationRecord
end

型
这是我计划如何创建它，但我得到和错误与dinner，我不知道为什么，与午餐和早午餐，我没有问题：

v1 = Meal.create(title: 'Meal 1', description: 'Desc 1')
v2 = Meal.create(title: 'Meal 2', description: 'Desc 2')
v3 = Meal.create(title: 'Meal 3', description: 'Desc 3')

day2 = Day.create(lunch: v1) # fine
day3 = Day.create(lunch: v1, brunch: v2) # fine

day1 = Day.create(lunch: v1, brunch: v2, dinner: v3) # error
day4 = Day.create(cena: v3, brunch: v2, lunch: v1) # error

WeeklyMenu.create(
  monday: day1,
  tuesday: day2,
  wednesday: day1,
  thursday: day2,
  friday: day3
)

型
我得到的错误：

Day Create (0.7ms)  INSERT INTO "days" ("lunch_id", "brunch_id", "dinner_id", "created_at", "updated_at") VALUES (?, ?, ?, ?, ?)  [["lunch_id", 6], ["brunch_id", 4], ["dinner_id", 5], ["created_at", "2023-07-03 02:21:40.793290"], ["updated_at", "2023-07-03 02:21:40.793290"]]
  TRANSACTION (0.1ms)  rollback transaction
/Users/dev/.rvm/gems/ruby-3.2.0/gems/sqlite3-1.6.3-arm64-darwin/lib/sqlite3/database.rb:152:in `initialize': SQLite3::SQLException: no such table: main.dinners (ActiveRecord::StatementInvalid)
/Users/dev/.rvm/gems/ruby-3.2.0/gems/sqlite3-1.6.3-arm64-darwin/lib/sqlite3/database.rb:152:in `initialize': no such table: main.dinners (SQLite3::SQLException)

型

ruby

来源：https://stackoverflow.com/questions/76601576/rails-database-system-initialize-no-such-table-main-dinners-sqlite3sqlex

1条答案

按热度按时间

z9ju0rcb1#

午餐和早午餐我没问题
day2 = Day.create（lunch：v1）# fine day3 = Day.create（lunch：v1，早午餐：v2）# fine
这并不好，因为Rails的失效开放设计。让我们来看看day2和day3：day2.valid2? => false的。
然后是示例中的最后一条错误消息：SQLite3::SQLException: no such table: main.dinners。Rails尝试引用不存在的dinners表。这是因为迁移的定义方式：

create_table :days do |t|
      t.references :lunch, null: false, foreign_key: true
      t.references :brunch, null: false, foreign_key: true
      t.references :dinner, null: false, foreign_key: true
    end

字符串
此架构无法按预期工作。您可以使用<meal>_id整数，如下所示：

create_table :days do |t|
  t.integer :lunch_id
  t.integer :brunch_id
  t.integer :dinner_id
end

型
使用外键：

create_table :days do |t|
  t.belongs_to :lunch, references: :meals, foreign_key: { to_table: 'meals' }
  t.belongs_to :brunch, references: :meals, foreign_key: { to_table: 'meals' }
  t.belongs_to :dinner, references: :meals, foreign_key: { to_table: 'meals' }
  t.timestamps
end

型

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ruby Rails数据库系统：`initialize '：无此表：一个表列出现main.dinners(SQLite3：：SQLException)错误，但其他列没有

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