numpy 如何根据python中预定的行和列将零矩阵变为一？

jchrr9hc 于 2023-08-05 发布在 Python

关注(0)|答案(2)|浏览(84)

现在，我有12x18的零矩阵：

zero = array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]])

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我突然想到了如何从这个列表中的一行中将0变为1

newArr2 = [[11, 17], 0, [5, 6], [13], [4], [16, 7], [4], [4], [1], 0, [8, 18], [18, 10]]

型
举例来说：第一行在列11和列17中从0变为1，并且当第二行为0时，没有变化。第三行在列5和列6中将0变为1。

array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]...]])

型
这是我的尝试：

for j in range (12):
    for i in range (len(newArr2[j])):
        rr=zero[j][newArr2[j][i]]=1

型
我不知道如何解决它。你能给予我推荐一下吗？谢啦，谢啦

numpy

来源：https://stackoverflow.com/questions/76795561/how-can-i-change-zero-matrix-to-one-according-to-the-predetermined-row-and-colu

2条答案

按热度按时间

flvtvl501#

我希望我的回答能有启发性。

import numpy as np

zero =np.array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
   [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]])

newArr2 = [[11, 17], 0, [5, 6], [13], [4], [16, 7], [4], [4], [1], 0, [8, 18], [18, 10]]

# zero = zero.reshape(1,-1)

for i in newArr2:
    if i != 0:
        if type(i) == list:
            for x in i:
                zero[newArr2.index(i), x-1] = 1
        if type(i) == int:
            zero[newArr2.index(i), i-1] = 1
        
print(zero)

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赞(0）回复(0）举报 2023-08-05

kupeojn62#

你可以试试这样的方法：

for i, x in enumerate(newArr2):
    if x==0:
        continue
    for j in x:
        zero[i][j-1]=1

字符串

赞(0）回复(0）举报 2023-08-05

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numpy 如何根据python中预定的行和列将零矩阵变为一？

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