在这个问题中,我必须用Python创建一个TicTacToe游戏,它将在终端中运行。这是一个2人游戏,如果任何玩家根据TicTacToe的规则获胜,则必须打印赢家= player 1/2。
我得到一个赢家声明时,我有三个或1的对角线,但我没有得到赢家在其他两种情况下(水平和垂直)
请帮助找到我的代码中的错误
import numpy as np
def create_board():
return (np.array([[0, 0, 0],
[0, 0, 0],
[0, 0, 0]]))
def coordinates(board, player):
i, j, cn = (-1, -1, 0)
while (i > 3 or i < 0 or j < 0 or j > 3) or (board[i][j] != 0):
if cn > 0:
print("Wrong Input! Try Again")
print("Player {}'s turn".format(player))
i = int(input("x-coordinates: "))
j = int(input("y-coordinates: "))
i = i - 1
j = j - 1
cn = cn + 1
board[i][j] = player
return board
def row_win(board, player):
for x in range(len(board)):
win = True
for y in range(len(board)):
if board[x, y] != player:
win = False
continue
return win
def col_win(board, player):
for x in range(len(board)):
win = True
for y in range(len(board)):
if board[y][x] != player:
win = False
continue
return win
def diag_win(board, player):
win = True
y = 0
for x in range(len(board)):
if board[x][x] != player:
win = False
if win:
return win
win = True
if win:
for x in range(len(board)):
y = len(board) - 1 - x
if board[x][y] != player:
win = False
return win
def evaluate(board):
winner = 0
for player in [1, 2]:
if (row_win(board, player) or
col_win(board, player) or
diag_win(board, player)):
winner = player
if np.all(board != 0) and winner == 0:
winner = -1
return winner
def play_game():
board, winner, counter = create_board(), 0, 1
print(board)
while winner == 0:
for player in [1, 2]:
board = coordinates(board, player)
print("Board after " + str(counter) + " move")
print(board)
counter += 1
winner = evaluate(board)
if winner != 0:
break
return winner
print("Winner is: " + str(play_game()))
字符串
1条答案
按热度按时间mfpqipee1#
假设这是董事会:
字符串
row_win
检查第一行,win
仍然是True
。然后继续检查第二行,将win
设置为False
。在最后一行之后,函数最终报告玩家没有赢,即使它赢了。要修复此问题,请将
row_win
和col_win
更改为如下所示:型
如果一行的所有单元格都等于该玩家,则该玩家获胜。如果没有一行的所有单元格都等于该玩家,则该玩家没有获胜。