假设有一个DataFrame，并且您希望按自定义组拆分：

groups = [['Alpha', 'Bravo'], ['Charlie', 'Delta']]

dfs = [g for _, g in df.groupby(df['Index'].map({k: v for v,l in enumerate(groups) for k in l}))]

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输出量：

dfs[0]

   Index Column1  Column2
0  Alpha  sample       12
1  Alpha  sample       13
2  Alpha  sample       14
3  Bravo  sample       15

dfs[1]

     Index Column1  Column2
4  Charlie  sample       16
5  Charlie  sample       17
6    Delta  sample       18
7    Delta  sample       19
8    Delta  sample       20
9    Delta  sample       21

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或者，如果“索引”实际上是索引：

groups = [['Alpha', 'Bravo'], ['Charlie', 'Delta']]

dfs = [df.loc[l] for l in groups]

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输出量：

dfs[0]

      Column1  Column2
Alpha  sample       12
Alpha  sample       13
Alpha  sample       14
Bravo  sample       15

dfs[1]

        Column1  Column2
Charlie  sample       16
Charlie  sample       17
Delta    sample       18
Delta    sample       19
Delta    sample       20
Delta    sample       21

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最后，如果您没有明确的组合，而只是想要2个值的组（按顺序），那么用途：

dfs = [g for _,g in df.groupby(pd.factorize(df['Index'])[0]//2)]

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