下面的代码运行得很好(playground):
struct MyStruct<const B: bool>;
impl MyStruct<false> {
pub fn bar() {
println!("false");
}
}
impl MyStruct<true> {
pub fn bar() {
println!("true");
}
}
impl MyStruct<false> {
pub fn foo() {
MyStruct::<false>::bar()
}
}
impl MyStruct<true> {
pub fn foo() {
MyStruct::<true>::bar()
}
}
fn main() {
MyStruct::<false>::foo();
MyStruct::<true>::foo();
}
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其结果是:
false
true
型
另一方面,这段代码将失败(playground):
struct MyStruct<const B: bool>;
impl MyStruct<false> {
pub fn bar() {
println!("false");
}
}
impl MyStruct<true> {
pub fn bar() {
println!("true");
}
}
impl<const B: bool> MyStruct<B> {
pub fn foo() {
MyStruct::<B>::bar()
}
}
fn main() {
MyStruct::<false>::foo();
MyStruct::<true>::foo();
}
型
导致:
error[E0599]: no function or associated item named `bar` found for struct `MyStruct<B>` in the current scope
--> src/main.rs:16:24
|
1 | struct MyStruct<const B: bool>;
| ------------------------------- function or associated item `bar` not found for this
...
16 | MyStruct::<B>::bar()
| ^^^ function or associated item not found in `MyStruct<B>`
|
= note: the function or associated item was found for
- `MyStruct<false>`
- `MyStruct<true>`
型
我可以理解无限值类型的错误,但为什么是布尔类型呢?
有没有办法克服这一点?
2条答案
按热度按时间nhhxz33t1#
必须使用trait和泛型类型条件(playground):
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当然,该原理可以推广到
bool
(playground)以外的其他类型:型
zvms9eto2#
playground
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