下面的代码应该会找到你想要的模式，并删除除了匹配组1之外的所有内容。

import re

ln = "this is other expenses3 0.10 0.16 0.14 0.04 0.16"

pattern = 'other expenses'

print(re.sub(f'({pattern})' + r'\d', r'\g<1>', ln))

字符串
为您留下：

this is other expenses 0.10 0.16 0.14 0.04 0.16

型

import re

regex = r"(other expenses)\w+"

test_str = "this is other expenses3 0.10 0.16 0.14 0.04 0.16"
or
test_str =  this is other expenses4587 0.10 0.16 0.14 0.04 0.16

subst = "\1"


result = re.sub(regex, subst, test_str)

if result:
    print (result)

字符串

这可能会被认为是不优雅的，但

import re

    def trimparam(string,param):
        return re.sub('(?<='+param+')\S+','',string)

个字符