regex 如何替换分隔符之间的重复字符串？

jpfvwuh4 于 2023-08-08 发布在其他

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我需要替换分隔符中的一个文本序列，精确地替换它出现的次数。例如，我有这样的文本：

"Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH too but it doesn't moo; bah!"

字符串
我想替换每一个“哞;“&”和“RGH”之间有一个“A”，所以我期望：

"Cow says &ARGH but also &AAARGH and &AAAAARGH but it doesn't moo; bah!"

型
换句话说，我必须替换每一个“哞;“&”和“RGH”之间的“A”。我必须通过JavaScript使用单个regexp在整个文本上替换它（如果可能的话）我做了很多尝试，例如：

var a="Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH but it doesn't moo; bah!"
a=a.replace(/(?<=&)((moo;)\1?)+RGH/g,"A");
// a=a.replace(/&(moo;)+RGH/g,"A")
// a=a.replace(/&(?=moo;)\1RGH/g,"A"
console.log(a);

型
但没有明显的成功。这个想法是，每一个“哞;必须用“A”替换，只有当与其他“moo”沿着出现时;“s在“&”和“RGH”之间
有什么建议吗？谢谢你，谢谢

regex

来源：https://stackoverflow.com/questions/76649246/how-to-replace-a-repeated-string-between-delimiters

3条答案

按热度按时间

xuo3flqw1#

您可以将(moo;)*放入lookbehind和lookahead判断提示中。这样，正则表达式将匹配&和RGH之间的所有moo：

var a="Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH but it doesn't moo; bah!"
a=a.replace(/(?<=&(moo;)*)moo;(?=(moo;)*RGH)/g, 'A');
console.log(a);

字符串
基准测试：

的数据

<script benchmark data-count="1000000">

let a = "Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH too but it doesn't moo; bah!";

// @benchmark Unmitigated
a.replace(/(?<=&)(moo;)+(?=RGH)/g, m => 'A'.repeat(m.length / 4));

// @benchmark Alexander
a.replace(/(?<=&(moo;)*)(moo;)(?=(moo;)*RGH)/g, 'A');

</script>
<script src="https://cdn.jsdelivr.net/gh/silentmantra/benchmark/loader.js"></script>

型

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pw136qt22#

您还可以匹配moo;的所有连续序列，并向String#replace传递一个回调函数，该回调函数根据每个序列的长度替换每个序列。

let str = "Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH too but it doesn't moo; bah!";
let res = str.replace(/(?<=&)(moo;)+(?=RGH)/g, m => 'A'.repeat(m.length / 4));
console.log(res);

字符串

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irlmq6kh3#

因为你想替换每个出现的 “moo;“，您将只希望匹配单个出现，而不是一个序列。
您可以使用 look-around 语法来Assert “moo;“

(?<=&|moo;)moo;(?=RGH|moo;)

字符串

var string = 'Cow says &moo;RGH but also &moo;moo;moo;RGH and &moo;moo;moo;moo;moo;RGH too but it doesn\'t moo; bah!'
string = string.replace(/(?<=&|moo;)moo;(?=RGH|moo;)/g, 'A')

console.log(string)

型

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regex 如何替换分隔符之间的重复字符串？

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