如何在django中更改链接upload_to imagefield

t30tvxxf 于 2023-08-08 发布在 Go

关注(0)|答案(2)|浏览(93)

在我的产品模型中有一个类别字段，它指的是另一个表，在类别表中有一个标题字段，我希望每个图像保存在一个文件夹中，名称对应的类别__title

class ProductImage(models.Model):
    title = models.CharField(max_length=100)
    image = models.ImageField(upload_to='...')
    product = models.ForeignKey(Product, on_delete=models.CASCADE)

class Product(models.Model):
    category = models.ForeignKey(Category, on_delete=models.CASCADE)

class Category(models.Model):
    title = models.CharField(max_length=150, verbose_name='title', unique=True)

字符串

django

来源：https://stackoverflow.com/questions/76768201/how-to-make-changing-link-upload-to-imagefield-in-django

2条答案

按热度按时间

k4aesqcs1#

我们可以使用upload_to：https://docs.djangoproject.com/en/4.2/ref/models/fields/#django.db.models.FileField.upload_to
paths.py

def upload_product_image(instance, filename):
    # instance is ProductImage object
    # here whatever we want.
    return f"{instance.product.category.title}/{filename}"

字符串
models.py

from .paths import upload_product_image

class ProductImage(models.Model):
    image = models.ImageField(upload_to=upload_product_image)

型

赞(0）回复(0）举报 2023-08-08

flvtvl502#

import os

def image_upload_path(instance, filename):
    # Get the category title for the current product image
    category_title = instance.product.category.title
    # Join the category title with the filename to create the final path
    upload_path = os.path.join('product_images', category_title, filename)
    return upload_path

class ProductImage(models.Model):
    title = models.CharField(max_length=100)
    image = models.ImageField(upload_to=image_upload_path)
    product = models.ForeignKey(Product, on_delete=models.CASCADE)

字符串

赞(0）回复(0）举报 2023-08-08

我来回答

如何在django中更改链接upload_to imagefield

2条答案

相关问题

热门标签

最新问答