你可以写一个DoesCultureExist方法，返回一个布尔值，就像这样：

private static bool DoesCultureExist(string cultureName)
{
    return CultureInfo.GetCultures(CultureTypes.AllCultures).Any(culture => string.Equals(culture.Name, cultureName, StringComparison.CurrentCultureIgnoreCase));
}

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我认为没有这样的方法。因此，您可以只使用try-catch或检查所有已安装的区域性：

string cultureCode = "de-DE";
CultureInfo[] cultures = CultureInfo.GetCultures(CultureTypes.AllCultures & ~CultureTypes.NeutralCultures);
var culture = cultures.FirstOrDefault(c => c.Name.Equals(cultureCode, StringComparison.OrdinalIgnoreCase));
if (culture == null)
{
    culture = cultures.FirstOrDefault(c => c.Name.Equals(DefaultCultureCode, StringComparison.OrdinalIgnoreCase));
    if (culture == null)
        culture = CultureInfo.CurrentCulture;
}

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但我更喜欢try-catch，我相信它更有效。

public bool TryGetCultureInfo(string cultureCode, string DefaultCultureCode, out CultureInfo culture)
{
    try
    {
        culture = CultureInfo.GetCultureInfo(cultureCode);
        return true;
    } catch(CultureNotFoundException)
    {
        if (DefaultCultureCode == null)
            culture = CultureInfo.CurrentCulture;
        else
        {
            try
            {
                culture = CultureInfo.GetCultureInfo(DefaultCultureCode);
            } catch (CultureNotFoundException)
            {
                culture = CultureInfo.CurrentCulture;
            }
        }
    }
    return false;
}

型

如果你想让它更快，你可以用途：

internal static class Culture
{
    private static readonly HashSet<string> CultureNames = CreateCultureNames();

    internal static bool Exists(string name)
    {
        return CultureNames.Contains(name);
    }

    private static HashSet<string> CreateCultureNames()
    {
        var cultureInfos = CultureInfo.GetCultures(CultureTypes.AllCultures)
                                      .Where(x => !string.IsNullOrEmpty(x.Name))
                                      .ToArray();
        var allNames = new HashSet<string>(StringComparer.OrdinalIgnoreCase);
        allNames.UnionWith(cultureInfos.Select(x => x.TwoLetterISOLanguageName));
        allNames.UnionWith(cultureInfos.Select(x => x.Name));
        return allNames;
    }
}

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不，AFAIK不可能。您可以先检查该区域性是否存在，如果存在，则获取它。
下面的代码显示了如何执行此操作：

private static CultureInfo GetCulture(string name)
    {
        if (!CultureExists(name)) return null;

        return CultureInfo.GetCultureInfo(name);
    }

    private static bool CultureExists(string name)
    {
        CultureInfo[] availableCultures =
            CultureInfo.GetCultures(CultureTypes.AllCultures);

        foreach (CultureInfo culture in availableCultures)
        {
            if (culture.Name.Equals(name))
                return true;
        }

        return false;
    }

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希望有帮助

对于那些可能感兴趣的人来说，从.NET 5开始，这个重载确实做到了这一点（有效地调用Nls或Icu本机API）。