这样的东西对你有用吗？

import json

with open ("myfile.json", 'r') as f:
    myjson = json.load(f)

# Add any top level keys you want to move into the `versions` key
versions_keys = [
    "pattern", "baseline"
]

myjson["versions"] = {}

for version_key in versions_keys:
    key = myjson.pop(version_key)
    myjson["versions"][version_key] = key

myjson = {'Main Parent': myjson}

print(json.dumps(myjson, indent=4))

字符串
pop方法从dict中删除键并返回其值。
我们存储该值并将其放回新的“versions”键下。
输出量：

{
    "Main Parent": {
        "target": {
            "Name": "abc",
            "Occupation": "xyz"
        },
        "properties": {
            "env": "dev"
        },
        "use_it": "xyz",
        "versions": {
            "pattern": {
                "provider": "abc",
                "schema": "xyz"
            },
            "baseline": {
                "version": "dev"
            }
        }
    }
}

型

是的，你可以动态地从versions字典中获取键，并将它们插入到JSON中的“pattern”键之前！
看看这个：

import json

with open("myfile.json", "r") as f:
    myjson = json.load(f)

versions = {
    "pattern": {
        "provider": "abc",
        "schema": "xyz"
    },
    "baseline": {
        "version": "dev"
    }
}

index = list(myjson).index("pattern")

updated_json = {}

for i, (key, value) in enumerate(myjson.items()):
    if key == "pattern":
        updated_json["versions"] = versions
    updated_json[key] = value

with open("myfile.json", "w") as f:
    json.dump(updated_json, f, indent=4)

字符串
正如您所看到的，versions字典是用所需的键值对定义的，并且在通过原始JSON迭代期间，当遇到pattern键时，versions字典会被插入到它之前！