如何在包含变量的字符串中添加自定义字符取决于组变量?
下面是虚拟输入数据集:
library(tidyverse)
unit <- c(50, 50, 40, 40, 30, 30, 20, 20, 10, 10)
id <- c("A100", "A101", "A102", "A103", "A100", "A101", "A102", "A103", "A101", "A100")
variation <- c("aaa1", "aaa1", "bbb1", "aaa2", "b1","a3", "a1", "b1", "a1", "b1" )
result <- c("Way1", "Way1", "Way2", "Way2", "Way3","Way1", "Way2", "Way3", "Way4", "Way1" )
data <- data.frame(id, variation, result, unit)
head(data)
# id variation result unit
# 1 A100 aaa1 Way1 50
# 2 A101 aaa1 Way1 50
# 3 A102 bbb1 Way2 40
# 4 A103 aaa2 Way2 40
# 5 A100 b1 Way3 30
# 6 A101 a3 Way1 30
# 7 A102 a1 Way2 20
# 8 A103 b1 Way3 20
# 9 A101 a1 Way4 10
# 10 A100 b1 Way1 10
是否可以在“变量”列中添加自定义字符串字符取决于“单位”列?
下面是预期的输出:
# id variation result unit
# 1 A100 A1.aaa1 Way1 50
# 2 A101 A1.aaa1 Way1 50
# 3 A102 A2.bbb1 Way2 40
# 4 A103 A2.aaa2 Way2 40
# 5 A100 A3.b1 Way3 30
# 6 A101 A3.a3 Way1 30
# 7 A102 A4.a1 Way2 20
# 8 A103 A4.b1 Way3 20
# 9 A101 A5.a1 Way4 10
# 10 A100 A5.b1 Way1 10
正如你所看到的,如果“unit”变量是相同的,那么相同的自定义字符串被添加到“variation”变量。
优选dplyr和base R函数。
1条答案
按热度按时间eeq64g8w1#
输出量:
注意:最好只创建一个组列,而不是创建这个。开头的那封信似乎没有增加任何东西。