我以前用过几次Lumenworks CSV阅读器，从来没有见过这个问题。我有一个简单的CSV文件：

"1","001333","Test Company","","123 Test St","","Eland","NS","58601","USA","","","","","Company 1","","123 Destination St","","Schefield","ND","58601","USA","","","Standard No Options","Label 001","2","1","5","","","","","0","0","0","0","0","0","0","0","0","0","0","05/02/2023","001333","0"
"1","001333","Test Company","","123 Test St","","Eland","NS","58601","USA","","","","","Company 1","","123 Destination St","","Schefield","ND","58601","USA","","","Standard No Options","Label 001","2","2","125","","","","","0","0","0","0","0","0","0","0","0","0","0","05/02/2023","001333","0"

我通过创建一个新的流来阅读它，在顶部指定了头定义，然后复制文件流，这样我就读取了一个带头的CSV。
这是一个非常简单的代码摘录：

using StreamReader filestream = new StreamReader(csvfilepath);
using var finalcsvstream = await PrependHeaderToStream(filestream);
using var csv = new CsvReader(finalcsvstream, true);
while (csv.ReadNextRecord())
{
  var fileversionnumber = csv["FileVersionNumber"];
  var field2 = csv["field2"];
  // etc
}

FileVersionNumber是第一列，也是我唯一遇到问题的列。在文件中，它显然是数字1，但当我读取它时，我得到了一个带转义双引号的字符串：

\"1\"

经过一个多小时的工具和搜索谷歌，我已经尝试指定分隔符和引号，发挥各种修剪选项都无济于事。我查看了库的一个分支的源代码，看起来不应该发生这种情况。目前，我需要这个工作，并提出了一个具体的变通办法来修剪这个列。
你知道哪里出了问题吗？我应该做一个完整的工作玩具的例子，看看问题是否仍然存在？
我还应该提到，我尝试了带双引号和不带双引号的标题，看看它是否会做任何事情。
编辑：我的CSV文件的源代码是一个base64编码的字符串。人们会认为这将是安全的任何疯狂的字符恶作剧。当我在记事本中打开文件时，它看起来很好，但是如果我将base64字符串写入磁盘并使用以下内容：

base64 -d < /tmp/b64.txt | hexdump -c

我看到以下内容：

0000000 357 273 277   "   1   "   ,   "   0   0   1   3   3   3   "   ,
0000010   "   T   e   s   t       C   o   m   p   a   n   y   "   ,   "

有什么建议，如何修剪之前，在lumenworks打开它的来源？