今天有一个奇怪的问题，我有一个bug，如果typeof(transaction)返回object而不是对象名称，代码的行为会有所不同。我修复了函数中transactionType参数的问题，但为了向后兼容，我不得不保留旧的逻辑。

let userId: string;
    
    if (transactionType === TransactionTypes.A) {
      userId = (transaction as TransactionA).userid;
    } else if (transactionType === TransactionTypes.B) {
      userId = (transaction as TransactionB).user.id;
    } else if (
      transactionType === TransactionC
    ) {
      userId = (transaction as TransactionC).userId;
    } else {
      console.log("LEGACY TRANSACTION TYPE USED...");
      // Legacy code, caused an issue when typeof returns "object"
      userId =
        (transaction as TransactionA).userid ||
        (transaction as TransactionC).userId ||
        (transaction as TransactionB).user.id;
    }

当typeof返回object时，我得到userId的null返回。我希望能够测试我的新TransactionType逻辑是否确实工作。
为此，我需要进行一个typeof返回object的测试。我尝试将以下内容传递给我的函数，但我的linter出现了类型错误。
下面是函数声明：

private getTransactionValues(
    transaction:
      | TransactionA
      | TransactionB
      | TransactionC,
    transactionType?: TransactionTypes,
    ): TransactionValues {
       //...
    }

我尝试让typeof返回object：

const transaction: TransactionB = (generateRandomTransaction() as Object);

getTransactionValues({
  transaction,
//~~~~~~~~~~~~ ^ error linter "object not TransactionA | TransactionB | TransactionC"
  transactionType: TransactionType.A,
});

是否可以用我的对象模拟一个属性，使它在传递给函数typeof时返回类型object？