pandas 散点图标记

yvt65v4c 于 2023-09-29 发布在其他

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使用google colab（类似于Jupyter notebook），我尝试读取cities.csv文件，格式为：城市，纬度，经度
我可以绘制图表**，但我似乎无法弄清楚如何将[城市]写在每个绘图点上方**。

import matplotlib
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np

col_names=['City','Lat','Long']
da = pd.read_csv('cities.csv',names=col_names,header=None,dtype=None)
print(da)

cityArray = da.City
x=da.Lat
y=da.Long

#df= pd.read_csv("cities.csv")
#df
#data = np.genfromtxt("cities.csv", delimiter=",", names=["city","x", "y"])
#print(data['city'])
#labels = [(data['city'])]
#print(labels)

plt.figure(figsize=(20,20))
plt.scatter(da.Long,da.Lat,s=20,color='red')
#for xz,yz in zip(x,y):
#  plt.text(x,y,'cityArray')
#plt.show();

cities.csv内容

Abilene,32.4543,-99.7384
Alice,27.7556,-98.0653
Amarillo,35.1989,-101.831
Austin,30.3006,-97.7517
Beaumont,30.085,-94.1451
Brownsville,25.998,-97.4565
College Station,30.5852,-96.296
Columbus,29.7055,-96.5563
Corpus Christi,27.7261,-97.3755
Dalhart,36.0579,-102.5123
Dallas,32.7936,-96.7662
Del Rio,29.3708,-100.88
El Paso,31.8479,-106.4309
Fort Worth,32.7812,-97.3472
Galveston,29.5112,-95.1979
Gonzalez,29.5126,-97.4472
Houston,29.7869,-95.3905
Jamaica Beach,29.1905,-94.9801
Kenedy,28.8176,-97.8518
Laredo,27.5617,-99.4874
Lubbock,33.5642,-101.8871
McAllen,26.2273,-98.2471
Midland,32.0249,-102.1137
New Braunfels,29.6997,-98.1148
Odessa,31.8831,-102.3406
Palestine,31.7544,-95.6471
Round Rock,30.5254,-97.6659
San Angelo,31.4426,-100.4501
San Antonio,29.4658,-98.5254
San Marcos,29.8736,-97.938
Seguin,29.5891,-97.9661
Sugar Land,29.5935,-95.6357
Temple,31.1076,-97.3894
Texarkana,33.4487,-94.0815
Three Rivers,28.4668,-98.1784
Uvalde,29.2153,-99.7782
Victoria,28.8285,-96.985
Waco,31.5597,-97.1882
Wichita Falls,33.9072,-98.529

pandas

来源：https://stackoverflow.com/questions/68051664/scatter-plot-labeling-at-plot-points

1条答案

按热度按时间

eimct9ow1#

试试这个：

col_names=['City','Lat','Long']
df = pd.read_clipboard(sep=',', names=col_names)

def label_point(x, y, val, ax):
    a = pd.concat({'x': x, 'y': y, 'val': val}, axis=1)
    for i, point in a.iterrows():
        ax.text(point['x']+.02, point['y'], str(point['val']))

ax = df.plot.scatter('Lat', 'Long', figsize=(12,8))
label_point(df['Lat'], df['Long'], df['City'], ax)

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pandas 散点图标记

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