如果这些是逐行的，你可以搜索'）.'序列，并使用这个正则表达式模式获得它后面的所有内容：\).([^\n]+)。
因此，在提供的示例中，您将在组1中获得<numbs and upper and lower case letters and _'s>"。

text = "<numbs and upper and lower case letters and _'s>(<numbs and upper and lower case letters and _'s>).<numbs and upper and lower case letters and _'s>"
split_text = text.split(').')

我认为使用split命令的最佳方法。否则，您可以尝试搜索字符位置并在找到索引后打印字符串：

string = "<numbs and upper and lower case letters and _'s>(<numbs and upper and lower case letters and _'s>).<numbs and upper and lower case letters and _'s>"

index = string.find(")")

if index != -1:
    result = string[index + 1:] ### To exclued also dot
    print(result)

代码：

import re

# Sample input string
input_string = "abc_def(123_ABC).xyz_456"

# Define the regular expression pattern
pattern = r'\)\.([a-zA-Z0-9_]+)'

# Use re.search to find the match
match = re.search(pattern, input_string)

# Check if a match was found
if match:
    # Extract the text following ').'
    result = match.group(1)
    print(result)
else:
    print("No match found.")

输入：“abc_def（123_ABC）.xyz_456”
输出：“xyz_456”

import re

string = "<numbs and upper and lower case letters and _'s>(<numbs and upper and lower case letters and_ 's>).<numbs and upper and lower case letters and \_'s>"

pattern = '\)\.(.*)'

match = re.search(pattern, string)
print(match.group(1))