你想把列表元素绑定在一起吗？rbind()：

# mock up data:
obj <- list(list("a","b"), list("a", "d"), list("c","d"))

# binding:
df <- do.call(rbind, obj)
df

> df
     [,1] [,2]
[1,] "a"  "b" 
[2,] "a"  "d" 
[3,] "c"  "d"

然后你只需要按照通常的方式对列名等进行排序。

你有几种可能性，让我们首先使用基R，然后也使用Tidyverse-way

# Option 1: Base R---------------------
# Don't use function names as identifiers, so I really recommend that "list"
# is renamed to sth like "multiple.lst" or sth. else. But will leave it for OP purposes.
list<- list(
  c("A", "C"),
  c("A", "D"),
  c("C", "D")
)

df <-
  do.call(rbind, lapply(list, function(x)
    data.frame(Source = x[1], Target = x[2])))

And the otuput:

  Source Target
1      A      C
2      A      D
3      C      D

#2 Tidyverse way------------------------
library(tidyverse)

df <- list %>% 
#  map_df: to iterate over each element of the list
  map_df(~data.frame(Source = .[1], Target = .[2]))

输出与选项1相同。