java 无法通过反射设置字段值

pinkon5k  于 2023-10-14  发布在  Java
关注(0)|答案(5)|浏览(111)

我不喜欢多对多的关系。这些表格是:成分和营养价值。我创建了两个实体之间的关系表,其中有成分和营养值的外部键(形成复合键)和一些属性。
JoinedNutrionalValueIngredient级:

import lombok.Data;
import javax.persistence.*;
import javax.validation.constraints.NotNull;
import java.io.Serializable;

@Entity @Data
public class JoinedNutrionalValueIngredient implements Serializable {

    @EmbeddedId
    private NutrionalValueIngredientId id;

    @ManyToOne(fetch= FetchType.LAZY)
    @MapsId("ingredient_id")
    private Ingredient ingredient;

    @ManyToOne(fetch=FetchType.LAZY)
    @MapsId("nutrional_value_id")
    private NutrionalValue nutrionalValue;

    @NotNull
    String matrixUnit;

    @NotNull
    int value;

    @NotNull
    String valueType;
}

NutrionalValueIngredientId类:

import javax.persistence.*;
import java.io.Serializable;
import java.util.Objects;

@Embeddable
@Getter
@Setter
public class NutrionalValueIngredientId implements Serializable{

    @Column(name = "ingredient_id")
    private Long ingredient_id;

    @Column(name = "nutrional_value_id")
    private Long nutrional_value_id;

    public NutrionalValueIngredientId() {
        
    }   
   
    public NutrionalValueIngredientId(Long ingredient, Long nutrionalValue){
        this.ingredient_id=ingredient;
        this.nutrional_value_id=nutrionalValue;
    }
    
    public boolean equals(Object o) {
        if (this == o) return true;
    
        if (o == null || getClass() != o.getClass())
            return false;
    
        NutrionalValueIngredientId that = (NutrionalValueIngredientId) o;
        return Objects.equals(ingredient_id, that.ingredient_id) &&
                    Objects.equals(nutrional_value_id, that.nutrional_value_id);
    }
    
    @Override
    public int hashCode() {
        return Objects.hash(ingredient_id, nutrional_value_id);
    }
}

当我试图在关系表中插入一个新字段时,我得到了这个错误:

{
  "timestamp": 1542653896247,
  "status": 500,
  "error": "Internal Server Error",
  "message": "Could not set field value [1] value by reflection : [class com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id] setter of com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id; nested exception is org.hibernate.PropertyAccessException: Could not set field value [1] value by reflection : [class com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id] setter of com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id",
  "path": "/v1/joinedNutrionalValueIngredients"
}

编辑:我添加了构造函数和注解@Getter@Setter,但我有同样的错误。
NutritionalValue类:

@Data
@Entity
public class NutrionalValue implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @NotNull
    private String name;

    @NotNull
    private String unit;

    @NotNull
    private String source;

    @ManyToOne
    @NotNull
    @JoinColumn(name = "category_id")
    private NutrionalValueCategory category;

    @OneToMany(mappedBy = "nutrionalValue")
    private Set<JoinedNutrionalValueIngredient> joined = new HashSet<JoinedNutrionalValueIngredient>();

}

编辑:Debopam的回答后,这个错误出来了。

{
  "timestamp": 1542657216244,
  "status": 500,
  "error": "Internal Server Error",
  "message": "null id generated for:class com.whateat.reciper.model.JoinedNutrionalValueIngredient; nested exception is org.hibernate.id.IdentifierGenerationException: null id generated for:class com.whateat.reciper.model.JoinedNutrionalValueIngredient",
  "path": "/v1/joinedNutrionalValueIngredients"
}
gudnpqoy

gudnpqoy1#

@Entity @Data
 public class JoinedNutrionalValueIngredient implements Serializable {
    
        @EmbeddedId
        private NutrionalValueIngredientId id = new NutrionalValueIngredientId();
    
    // ... rest of class  
 }

JoinedNutrionalValueIngredient类中,复合id NutrionalValueIngredientId应被示例化。

roejwanj

roejwanj2#

如下所示更改变量Names
长成分ID到长成分ID nutrional_value_id到nutrionalvalueid
例如

@Column(name = "ingredient_id")
  Long ingredient_id;

@Column(name = "ingredient_id")
Long ingredientid;

然后为所有字段生成getter setter。Hibernate无法设置字段,因为没有公共getter/setter。

pvcm50d1

pvcm50d13#

设置id实体“NutrionalValueDientId”的值,然后尝试将其作为“JoinedNutrionalValueDient”的嵌入id插入。参考以下示例:

package com.example;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Embeddable;

@Embeddable
public class EmployeeId implements Serializable
{
private static final long serialVersionUID = 1L;
@Column(name = "EMP_ID")
private int empId;
@Column(name = "DEPARTMENT")
private String department;

public EmployeeId()
{
    super();
}
public EmployeeId(int empId, String department)
{
    super();
    this.empId = empId;
    this.department = department;
}

public int getEmpId()
{
    return empId;
}
public void setEmpId(int empId)
{
    this.empId = empId;
}
public String getDepartment()
{
    return department;
}
public void setDepartment(String department)
{
    this.department = department;
}
@Override
public int hashCode()
{
    final int prime = 31;
    int result = 1;
    result = prime * result + ((department == null) ? 0 : department.hashCode());
    result = prime * result + empId;
    return result;
}
@Override
public boolean equals(Object obj)
{
    if (this == obj)
        return true;
    if (obj == null)
        return false;
    if (getClass() != obj.getClass())
        return false;
    EmployeeId other = (EmployeeId) obj;
    if (department == null)
    {
        if (other.department != null)
            return false;
    } else if (!department.equals(other.department))
        return false;
    if (empId != other.empId)
        return false;
    return true;
}
 }

参考上面的嵌入式ID类(Embedded Id)。这是Employee类的主键。因此,我们需要在ID class中设置值(ID ID)然后,将ID class注入到Employee作为主键。然后它会工作。如果没有主键,则该值为null。

package com.example;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity
public class Employee implements Serializable
{
private static final long serialVersionUID = 1L;
@EmbeddedId
EmployeeId id;
@Column(name="EMP_NAME")
private String empName;

public Employee()
{
    super();
}
public Employee(EmployeeId id, String empName)
{
    super();
    this.id = id;
    this.empName = empName;
}
public EmployeeId getId()
{
    return id;
}
public void setId(EmployeeId id)
{
    this.id = id;
}
public String getEmpName()
{
    return empName;
}
public void setEmpName(String empName)
{
    this.empName = empName;
}
}

设置ID类和其他字段的值,如下所示。

//Create a new Employee object   
 Employee employee = new Employee();

 EmployeeId employeeId = new EmployeeId(1,"DailyNews");
 employee.setEmpName("CompositeKey");
 employee.setId(employeeId);

 session.save(employee);
hc2pp10m

hc2pp10m4#

检查您是否正在为嵌入式ID设置示例。我没有得到这个错误。
我改变这个

@EmbeddedId
ProductUserId id;    

ProductUser(Integer productId, Integer UserId, Double rating){
    this.rating = rating
}

@EmbeddedId
ProductUserId id;    

ProductUser(Integer productId, Integer userId, Double rating){
    this.id = new ProductUserId(productId, userId);
    this.rating = rating
}
qrjkbowd

qrjkbowd5#

在我的例子中,发生的事情是,我试图持久化一个实体,该实体的组成ID带有一个空字段(因为错误说“为...生成了空ID”)。在你的例子中,我试图持久化一个这样的对象(参见ing):

JoinedNutrionalValueIngredientId wrongId = new JoinedNutrionalValueIngredientId(null, 435L)
JoinedNutrionalValueIngredient ing = new JoinedNutrionalValueIngredient(wrongId, ...);

在我的例子中,这个错误来自错误的DTO转换。为了解决这个问题,我简单地改变了逻辑,在持久化之前将这个字段设置为它的值。

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