mysql 内联接不适用于递归选择

bd1hkmkf  于 2023-10-15  发布在  Mysql
关注(0)|答案(1)|浏览(89)

我有几张table:

product(id)

product_locale(product_id, locale_id)

category_product(category_id, product_id)

我想选择一个类别的所有产品和它的子类别。
以下是我的查询:

SELECT a.id,
       a.added,
       a.seller,
       a.position,
       c.title,
       c.alias
FROM product a
INNER JOIN product_locale c ON a.id = c.product_id
INNER JOIN category_product d ON d.product_id = a.id
WHERE c.locale_id = 1
  AND (d.category_id = 17
       OR d.category_id in
         (SELECT id
          FROM
            (SELECT *
             FROM category
             ORDER BY parent,
                      id) category_sorted,

            (SELECT @pv := 17) initialisation
          WHERE find_in_set(parent, @pv)
            AND length(@pv := concat(@pv, ',', id))))
LIMIT 0,
      10

基本上,我有一个子查询来获取当前类别的所有子类别:

SELECT id
FROM
  (SELECT *
   FROM category
   ORDER BY parent,
            id) category_sorted,

  (SELECT @pv := 17) initialisation
WHERE find_in_set(parent, @pv)
  AND length(@pv := concat(@pv, ',', id))

下面是categories结构:
17 > 19 > 33 > 35
如果我单独运行子查询,我得到了正确的结果(19,33和35),所以我希望查询应该是:

SELECT a.id,
       a.added,
       a.seller,
       a.position,
       c.title,
       c.alias
FROM product a
INNER JOIN product_locale c ON a.id = c.product_id
INNER JOIN category_product d ON d.product_id = a.id
WHERE c.locale_id = 1
  AND (d.category_id = 17
       OR d.category_id in (19,
                            33,
                            35))
LIMIT 0,
      10

如果我运行这个查询,我得到了正确的结果。但是,如果我运行带有子查询的查询,则不会返回任何记录。
如果我使用左连接而不是内部连接,就像下面的查询一样,它可以工作:

SELECT a.id,
       a.added,
       a.seller,
       a.position,
       c.title,
       c.alias
FROM product a
LEFT JOIN product_locale c ON a.id = c.product_id
AND c.locale_id = 1
INNER JOIN category_product d ON d.product_id = a.id
WHERE (d.category_id = 17
       OR d.category_id in
         (SELECT id
          FROM
            (SELECT *
             FROM category
             ORDER BY parent,
                      id) category_sorted,

            (SELECT @pv := 17) initialisation
          WHERE find_in_set(parent, @pv)
            AND length(@pv := concat(@pv, ',', id))))
LIMIT 0,
      10

但是如果我将条件c.locale_id = 1移动到where condition,它就不起作用了:

SELECT a.id,
       a.added,
       a.seller,
       a.position,
       c.title,
       c.alias
FROM product a
LEFT JOIN product_locale c ON a.id = c.product_id
INNER JOIN category_product d ON d.product_id = a.id
WHERE c.locale_id = 1
  AND (d.category_id = 17
       OR d.category_id in
         (SELECT id
          FROM
            (SELECT *
             FROM category
             ORDER BY parent,
                      id) category_sorted,

            (SELECT @pv := 17) initialisation
          WHERE find_in_set(parent, @pv)
            AND length(@pv := concat(@pv, ',', id))))
LIMIT 0,
      10

我期望子查询不会影响查询,然而,似乎它确实如此。

h6my8fg2

h6my8fg21#

请使用以下代码:

SELECT a.id,
       a.added,
       a.seller,
       a.position,
       c.title,
       c.alias
FROM product a
INNER JOIN product_locale c ON a.id = c.product_id AND c.locale_id = 1
INNER JOIN (
    SELECT id
    FROM (
        SELECT *
        FROM category
        ORDER BY parent, id
    ) category_sorted
    JOIN (
        SELECT @pv := 17
    ) initialisation
    WHERE FIND_IN_SET(parent, @pv) AND LENGTH(@pv := CONCAT(@pv, ',', id))
) subcategories ON d.category_id = subcategories.id
LIMIT 0, 10;

我已经将c.locale_id = 1条件移回了带有product_locale的INNER JOIN中,确保您只检索与locale匹配的产品。

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