#include <stdio.h>
#include <omp.h>

#define N 5

int X[N];

int main() {
    int num = 0;
    int moy = 0;

    // Initialize the array (you should populate it as needed)
    for (int i = 0; i < N; i++) {
        X[i] = i * 2; // Example initialization
    }

    // Calculate the average
    #pragma omp parallel for reduction(+:moy)
    for (int i = 0; i < N; i++) {
        moy += X[i] / N;
    }

    // Count elements greater than the average
    #pragma omp parallel for reduction(+:num)
    for (int i = 0; i < N; i++) {
        if (X[i] > moy) {
            num++;
        }
    }

    printf("%d\n", num);

    return 0;
}

如果我为数组的mean、num和elements编写print语句，我会得到以下输出：
平均值（百万美元）：2
X中的元素：0 2 4 6 8
大于平均值的元素数：3