我没有使用C的经验,我需要使用PCRE来获得匹配。
下面是我的源代码示例:
int test2()
{
const char *error;
int erroffset;
pcre *re;
int rc;
int i;
int ovector[OVECCOUNT];
char *regex = "From:([^@]+)@([^\r]+)";
char str[] = "From:[email protected]\r\n"\
"From:[email protected]\r\n"\
"From:[email protected]\r\n";
re = pcre_compile (
regex, /* the pattern */
0, /* default options */
&error, /* for error message */
&erroffset, /* for error offset */
0); /* use default character tables */
if (!re) {
printf("pcre_compile failed (offset: %d), %s\n", erroffset, error);
return -1;
}
rc = pcre_exec (
re, /* the compiled pattern */
0, /* no extra data - pattern was not studied */
str, /* the string to match */
strlen(str), /* the length of the string */
0, /* start at offset 0 in the subject */
0, /* default options */
ovector, /* output vector for substring information */
OVECCOUNT); /* number of elements in the output vector */
if (rc < 0) {
switch (rc) {
case PCRE_ERROR_NOMATCH:
printf("String didn't match");
break;
default:
printf("Error while matching: %d\n", rc);
break;
}
free(re);
return -1;
}
for (i = 0; i < rc; i++) {
printf("%2d: %.*s\n", i, ovector[2*i+1] - ovector[2*i], str + ovector[2*i]);
}
}
在本演示中,输出仅为:0: From: [[email protected]](https://stackoverflow.com/cdn-cgi/l/email-protection)
1: regular.expressions
2: example.com
我想输出所有的匹配;我该怎么做?
2条答案
按热度按时间ltqd579y1#
我使用一个类来 Package PCRE以使其更容易,但在pcre_exec之后,ovector包含在原始字符串中查找匹配所需的子字符串索引。
所以它应该是这样的:
ryevplcw2#
注意:pcre_exec()的最后一个参数必须是element-count,而不是sizeof()!(http://www.pcre.org/readme.txt)