传统上，你在usage（）函数中记录你的参数：

#!/bin/bash

programname=$0

function usage {
    echo "usage: $programname [-abch] [-f infile] [-o outfile]"
    echo "  -a      turn on feature a"
    echo "  -b      turn on feature b"
    echo "  -c      turn on feature c"
    echo "  -h      display help"
    echo "  -f infile   specify input file infile"
    echo "  -o outfile  specify output file outfile"
    exit 1
}

usage

我通常把我的用法 Package 在函数中，这样我就可以从-h参数调用它。

#!/bin/bash
usage() {
    cat <<EOM
    Usage:
    $(basename $0) Explain options here

EOM
    exit 0
}

[ -z $1 ] && { usage; }

我会使用Heredoc重新评论：

usage () {
    cat <<HELP_USAGE

    $0  [-a] -f <file>

   -a  All the instances.
   -f  File to write all the log lines
HELP_USAGE
}

而不是：

echo "$0  [-a] -f <file>"
echo
echo "-a  All the instances."
echo "-f  File to write all the log lines."

我认为它比所有这些回声线都要干净。

Vim bash IDE可以做到这一点：

#!/bin/bash
#===============================================================================
#
#          FILE:  test.sh
#
#         USAGE:  ./test.sh
#
#   DESCRIPTION:
#
#       OPTIONS:  ---
#  REQUIREMENTS:  ---
#          BUGS:  ---
#         NOTES:  ---
#        AUTHOR:  Joe Brockmeier, [email protected]
#       COMPANY:  Dissociated Press
#       VERSION:  1.0
#       CREATED:  05/25/2007 10:31:01 PM MDT
#      REVISION:  ---
#===============================================================================

我建议让你的脚本自动打印用法（如果它不应该在没有参数的情况下运行）：

#!/usr/bin/env bash

if [ $# == 0 ]; then
    echo "Usage: $0 param1 [param2]"
    echo "* param1: <description>"
    echo "* param2: <description>"
fi

我宁愿写：

Usage: `basename $0` [option1]|[option2] param1
  Options:
   - option1:  .....
   - option2:  .....
  Parameters:
   - param1:   .....

尝试查看标准UNIX实用程序（例如ls --help）的帮助格式

基于@eddy的excellent answer，下面是处理多个参数的版本（在本例中为2）

#!/bin/bash

usage() {
    cat <<EOM
Usage: $(basename $0) <username> <myproject> 
where 
  <username> is your user name
  <myproject> is your project's name
EOM
    exit 1
}

[ $# != 2 ] && { usage; }
for arg in "$@"
do
    [ -z "$arg" ] && { usage; }
done

需要仔细检查参数数组的长度（[ $# != 2 ]）以及参数是否为null（[ -z "$arg" ]），以处理作为参数给出的空字符串。