我试图在pickup-address
类中获取值,但收效甚微。这是我目前为止的代码。我做错了什么?
JS
var pickupAddress = $('.timeline-item.active-item > .timeline-status > .pickup-address').val();
alert(pickupAddress);
HTML
<div class="timeline-item active-item" style="background-color: rgb(255, 255, 255);">
<img src="https://s3.amazonaws.com/uifaces/faces/twitter/jsa/128.jpg" alt="" class="img-rounded profile">
<div class="timeline-status" style="width: 185px;"><strong>Stephen
</strong>
<br><span class="pickup-address">Whaddon</span> — <span class="dropoff-address">Bancroft</span>
<br><span class="timeline-substatus grey-status waypoints">Via Lathbury</span>
<br><span class="timeline-substatus grey-status remaining-seats">3 places remaining</span>
</div>
</div>
2条答案
按热度按时间bpzcxfmw1#
使用.text或.html代替
.val
,因为pickup-address
不是input
字段Example
dm7nw8vv2#
使用text()代替瓦尔()。我认为瓦尔()只对inputs元素起作用。