我试图拉数据从一个Web服务使用Apache Camel 。但是对于相同的API，我得到了正确的JSON响应以及不同过滤条件的异常。
例如：
http://student.com/rest/student-id/44
这里44是有效学生ID
我将给予我正确的JSON响应和无CXF异常
但是，当我用一个无效的学生ID命中，说'1n23'，webservivce将返回一个正确的错误JSON

{
  "error": "No record found."
}

但在 Camel 中，

org.apache.cxf.transport.http.HTTPException: HTTP response '404: null' when communicating with http://student.com/rest/student-id/1n23
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponseInternal(HTTPConduit.java:1581) ~[cxf-rt-transports-http-3.0.4.jar:3.0.4]
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream$1.run(HTTPConduit.java:1155) ~[cxf-rt-transports-http-3.0.4.jar:3.0.4]
    at org.apache.cxf.workqueue.AutomaticWorkQueueImpl$3.run(AutomaticWorkQueueImpl.java:428) [cxf-core-3.0.4.jar:3.0.4]
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) [na:1.8.0_102]
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) [na:1.8.0_102]
    at org.apache.cxf.workqueue.AutomaticWorkQueueImpl$AWQThreadFactory$1.run(AutomaticWorkQueueImpl.java:353) [cxf-core-3.0.4.jar:3.0.4]
    at java.lang.Thread.run(Thread.java:745) [na:1.8.0_102]

这是我的 Camel 路线

<route streamCache="true" id="StudentService">
            <from uri="servlet:{{student.service.url.relative}}" />             
            <to uri="bean:RequestProcessor?method=buildReq" />
            <to uri="log:camelRouteLogger?showHeaders=true" />
            <recipientList>
                <simple>cxf://?dataFormat=MESSAGE&amp;loggingFeatureEnabled=true</simple>
            </recipientList>                
            <to uri="log:camelRouteLogger?showHeaders=true" />
        </route>

请求处理器

public void buildReq(final Exchange exchange) {
        try {
            final HttpMessage httpMessage = exchange.getIn(HttpMessage.class);              
            String serviceUrl = StudentUrlWithStudentCode;              
            exchange.setOut(new DefaultMessage());
            final Map<String, Object> map = new HashMap<String, Object>();
            map.put(Message.HTTP_REQUEST_METHOD, "GET");
            exchange.getOut().setHeader(Client.REQUEST_CONTEXT, map);
            exchange.getOut().setHeader(Exchange.DESTINATION_OVERRIDE_URL, serviceUrl);
            exchange.getOut().setHeader("API-KEY", "xxxxxxxxxxxxxxxxxxxxxxxxxxxxx");
            exchange.getOut().setHeader("Accept", "application/json");
            exchange.getOut().setBody("-");
        } catch (Exception e) {
            LOGGER.error(e.getMessage());
        }
    }

编辑我在路由中添加了以下内容

<onException>
  <exception>org.apache.cxf.transport.http.HTTPException</exception>
  <handled>
     <constant>true</constant>
  </handled>                
  <bean ref="stdErrorHandler" method="errorHandler"/>       
</onException>

在标准错误中

public void errorHandler(final Exchange exchange, @Body String payload ){
            System.out.println(payload);        
    }

在这里，我将只收到我设置的假人身体

exchange.getOut().setBody("Dummy Body");

我将如何获得响应有效载荷。