example.py源代码：

from typing import Union, Any
import numpy as np

Number = Union[int, float, np.floating[Any]]

def add_one(num: Number) -> Number:
    return num + 1

inputs = [1, 2, 3]
outputs = [add_one(n) for n in inputs]

avg = np.mean(outputs)

运行mypy：

mypy example.py
src/example.py:14: error: Argument 1 to "mean" has incompatible type "List[Union[float, floating[Any]]]"; expected "Union[_SupportsArray[dtype[Any]], _NestedSequence[_SupportsArray[dtype[Any]]], bool, int, float, complex, str, bytes, _NestedSequence[Union[bool, int, float, complex, str, bytes]]]"
Found 1 error in 1 file (checked 1 source file)

我可以将所有内容都更改为np.floating[Any]，这解决了numpy问题，但之后我必须将原语转换为np.float32(...)：

from typing import Any
import numpy as np

def add_one(num: np.floating[Any]) -> np.floating[Any]:
    return num + 1

inputs = [1, 2, 3]
outputs = [add_one(np.float32(n)) for n in inputs]

avg = np.mean(outputs)

有没有一种正确的方法来类型提示add_one函数，使其输出与numpy函数（如np.mean）兼容，而不破坏与python基本类型的兼容性？最终目标是能够像这样使用它：

inputs = [1, 2, 3]
outputs = [add_one(n) for n in inputs]
avg = np.mean(outputs)