使用自定义函数查找2个阵列和符合给定公差的位置之间的绝对差异：

array1 = np.array([1, 2, 3, 4, 5, 6])
array2 = np.array([2, 8, 1.00001, 1.1])
tolerance = 0.001

def argwhere_close(a, b, tol):
    return np.where(np.any(np.abs(a - b[:, None]) <= tolerance, axis=0))[0]

print(argwhere_close(array1, array2, tolerance))

[0 1]

虽然我不知道numpy中有什么函数，但我确实写了一个。
希望这对你有帮助：

import numpy as np

def find_indices_within_tolerance(array1, array2, tolerance):
    results = []
    for i, a1_elem in enumerate(array1):
        for a2_elem in array2:
            if abs(a1_elem - a2_elem) <= tolerance:
                results.append(i)
    results = list(set(results))
    results.sort()
    return results

array1 = np.array([1, 2, 3, 4, 5, 6])
array2 = np.array([2, 8, 1.00001, 1.1])

places = find_indices_within_tolerance(array1, array2, tolerance=0.001)

print(places)

-> yields: [0, 1]