要创建带注解图像的COCO数据集,您需要根据对象的类型将二进制掩码转换为多边形或未压缩的游程长度编码表示。
pycocotools库具有对 compressed RLE进行编码和解码的功能,但没有多边形和未压缩RLE的功能。
我可以使用skimage的measure库来generate polygons of masks,但我不确定如何创建未压缩的RLE。
我可以使用this RLE encoder从图像创建RLE的 a 表示,但我不确定COCO期望什么格式。COCO只是提到他们使用“自定义游程编码(RLE)方案”
例如,
ground_truth_binary_mask = np.array([[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 1, 1, 1, 0, 0],
[ 0, 0, 0, 0, 0, 1, 1, 1, 0, 0],
[ 0, 0, 0, 0, 0, 1, 1, 1, 0, 0],
[ 0, 0, 0, 0, 0, 1, 1, 1, 0, 0],
[ 1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]], dtype=np.uint8)
fortran_ground_truth_binary_mask = np.asfortranarray(ground_truth_binary_mask)
rle(fortran_ground_truth_binary_mask)
产出:
(array([26, 36, 46, 56, 61]), array([3, 3, 3, 3, 1]))
这就是Coco RLE的样子:
{
"segmentation": {
"counts": [
272,
2,
4,
4,
4,
4,
2,
9,
1,
2,
16,
43,
143,
24,
5,
8,
16,
44,
141,
25,
8,
5,
17,
44,
140,
26,
10,
2,
17,
45,
129,
4,
5,
27,
24,
5,
1,
45,
127,
38,
23,
52,
125,
40,
22,
53,
123,
43,
20,
54,
122,
46,
18,
54,
121,
54,
12,
53,
119,
57,
11,
53,
117,
59,
13,
51,
117,
59,
13,
51,
117,
60,
11,
52,
117,
60,
10,
52,
118,
60,
9,
53,
118,
61,
8,
52,
119,
62,
7,
52,
119,
64,
1,
2,
2,
51,
120,
120,
120,
101,
139,
98,
142,
96,
144,
93,
147,
90,
150,
87,
153,
85,
155,
82,
158,
76,
164,
66,
174,
61,
179,
57,
183,
54,
186,
52,
188,
49,
191,
47,
193,
21,
8,
16,
195,
20,
13,
8,
199,
18,
222,
17,
223,
16,
224,
16,
224,
15,
225,
15,
225,
15,
225,
15,
225,
15,
225,
15,
225,
15,
225,
15,
225,
15,
225,
14,
226,
14,
226,
14,
39,
1,
186,
14,
39,
3,
184,
14,
39,
4,
183,
13,
40,
6,
181,
14,
39,
7,
180,
14,
39,
9,
178,
14,
39,
10,
177,
14,
39,
11,
176,
14,
38,
14,
174,
14,
36,
19,
171,
15,
33,
32,
160,
16,
30,
35,
159,
18,
26,
38,
158,
19,
23,
41,
157,
20,
19,
45,
156,
21,
15,
48,
156,
22,
10,
53,
155,
23,
9,
54,
154,
23,
8,
55,
154,
24,
7,
56,
153,
24,
6,
57,
153,
25,
5,
57,
153,
25,
5,
58,
152,
25,
4,
59,
152,
26,
3,
59,
152,
26,
3,
59,
152,
27,
1,
60,
152,
27,
1,
60,
152,
86,
154,
80,
160,
79,
161,
42,
8,
29,
161,
41,
11,
22,
2,
3,
161,
40,
13,
18,
5,
3,
161,
40,
15,
2,
5,
8,
7,
2,
161,
40,
24,
6,
170,
35,
30,
4,
171,
34,
206,
34,
41,
1,
164,
34,
39,
3,
164,
34,
37,
5,
164,
34,
35,
10,
161,
36,
1,
3,
28,
17,
155,
41,
27,
16,
156,
41,
26,
17,
156,
41,
26,
16,
157,
27,
4,
10,
25,
16,
158,
27,
6,
8,
11,
2,
12,
6,
2,
7,
159,
27,
7,
14,
3,
4,
19,
6,
160,
26,
8,
22,
18,
5,
161,
26,
8,
22,
18,
4,
162,
26,
8,
23,
15,
4,
164,
23,
11,
23,
11,
7,
165,
19,
17,
22,
9,
6,
167,
19,
22,
18,
8,
3,
170,
18,
25,
16,
7,
1,
173,
17,
28,
15,
180,
17,
30,
12,
181,
16,
34,
6,
184,
15,
225,
14,
226,
13,
227,
12,
228,
11,
229,
10,
230,
9,
231,
9,
231,
9,
231,
9,
231,
8,
232,
8,
232,
8,
232,
8,
232,
8,
232,
8,
232,
7,
233,
7,
233,
7,
233,
7,
233,
8,
232,
8,
232,
8,
232,
9,
231,
9,
231,
9,
231,
10,
230,
10,
230,
11,
229,
13,
227,
14,
226,
16,
224,
17,
223,
19,
221,
23,
217,
31,
3,
5,
201,
39,
201,
39,
201,
39,
201,
39,
201,
39,
201,
40,
200,
40,
200,
41,
199,
41,
199,
41,
199,
22,
8,
12,
198,
22,
12,
8,
198,
22,
14,
6,
198,
22,
15,
6,
197,
22,
16,
5,
197,
22,
17,
5,
196,
22,
18,
4,
196,
22,
19,
4,
195,
22,
19,
5,
194,
22,
20,
4,
194,
25,
21,
1,
193,
27,
213,
29,
211,
30,
210,
35,
6,
6,
193,
49,
191,
50,
190,
50,
190,
51,
189,
51,
189,
52,
188,
53,
187,
53,
187,
54,
186,
54,
186,
54,
186,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
55,
185,
28,
1,
26,
185,
23,
11,
21,
185,
20,
17,
17,
186,
18,
21,
15,
186,
16,
23,
14,
187,
14,
25,
14,
187,
14,
26,
12,
188,
14,
28,
10,
188,
14,
226,
14,
226,
16,
224,
17,
223,
19,
221,
20,
220,
22,
218,
24,
18,
3,
12,
3,
180,
25,
10,
1,
4,
6,
10,
6,
178,
28,
7,
12,
8,
8,
177,
49,
3,
12,
176,
65,
175,
67,
173,
69,
171,
53,
3,
14,
170,
37,
20,
9,
4,
1,
169,
36,
21,
8,
175,
35,
22,
7,
176,
34,
23,
7,
176,
34,
23,
6,
177,
35,
22,
6,
177,
35,
22,
8,
175,
35,
23,
9,
173,
35,
205,
36,
204,
39,
201,
43,
197,
48,
36,
1,
155,
48,
35,
3,
154,
49,
33,
5,
154,
48,
32,
6,
155,
49,
27,
10,
155,
51,
24,
11,
154,
54,
21,
11,
155,
56,
19,
11,
155,
56,
18,
11,
156,
56,
17,
11,
157,
56,
16,
12,
157,
56,
14,
13,
159,
56,
12,
13,
160,
61,
5,
14,
162,
78,
165,
75,
167,
73,
168,
72,
170,
70,
171,
69,
173,
67,
176,
64,
179,
61,
182,
58,
183,
57,
185,
54,
187,
53,
188,
51,
191,
49,
192,
47,
195,
45,
196,
43,
198,
42,
199,
40,
201,
38,
203,
36,
205,
34,
207,
32,
210,
28,
213,
26,
216,
22,
221,
16,
228,
8,
10250
],
"size": [
240,
320
]
}
}
5条答案
按热度按时间kqlmhetl1#
有关格式的信息可在此处获得:https://github.com/cocodataset/cocoapi/blob/master/PythonAPI/pycocotools/mask.py
RLE是用于存储二进制掩码的简单而有效的格式。RLE首先将矢量(或矢量化图像)划分为一系列分段恒定区域,然后针对每一段简单地存储该段的长度。例如,给定M=[0 0 1 1 1 0 1],RLE计数将是[2 3 1 1],或者对于M=[1 1 1 1 1 1 0],计数将是[0 6 1](注意奇数计数总是零的数量)。
产出:
您可以使用
mask.frPyObjects(rle, size_x, size_y)
对RLE进行编码,然后执行所有常见的mask
操作。将掩码编码为RLE:
产出:
压缩RLE,然后解码:
产出:
56lgkhnf2#
作为对@waspinator的回答的改进。速度快了35%。
44u64gxh3#
为了解码COCO注解中编码的二进制掩码,您需要首先使用COCO's API获得RLE,然后使用opencv获得如下轮廓:
COCO stuff 2017
注解使用二进制掩码,COCO person 2017
注解没有,所以你不需要解码后者并找到它们的轮廓。受此解决方案的启发。
wfveoks04#
这样做:
tquggr8v5#
我用numpy改进了@waspinator和@Carl Cheung的代码,现在比以前快了。灵感来自find consecutive numbers in a list。