我声明了@ transmitting，但仍然得到错误：无法懒惰地初始化一个角色集合：fa.training.model.KhachHang.suDungMay，无法初始化代理-无会话。
具体而言：在AllCustomerInfoController类中，我希望获得使用SuDungMay和SuDungDichVu的所有客户的列表：

@Controller
public class AllCustomerInfoController {

    @Autowired
    private KhachHangRepository khachHangRepository;

    @GetMapping(value = "/")
    @Transactional
    public String allCustomerInfo(Model model) {
        List<KhachHang> listKhachHang = khachHangRepository.findAll();
        model.addAttribute("listAllCustomer", listKhachHang);
        return "allcustomerinfo";
    }
}

我的实体类：

@Entity
public class KhachHang {

    @Id
    private String maKh;
    private String tenKh;
    private String diaChi;
    private String sdt;
    private String email;
    @OneToMany(cascade = CascadeType.ALL, mappedBy = "khachHang")
    private List<SuDungMay> suDungMay;
    @OneToMany(cascade = CascadeType.ALL, mappedBy = "khachHang")
    private List<SuDungDichVu> suDungDichVu;
}

@Entity
public class SuDungDichVu {
    @Valid
    @EmbeddedId
    private SuDungDichVuId suDungDichVuId;
    private int soLuong;
    @ManyToOne
    @JoinColumn(name = "maKh")
    @MapsId(value = "maKh")
    private KhachHang khachHang;
    @ManyToOne
    @JoinColumn(name = "maDv")
    @MapsId(value = "maDv")
    private DichVu dichVu;
}

@Entity
public class SuDungMay {
    @EmbeddedId
    @Valid
    private SuDungMayId suDungMayId;
    private double thoiGianSd;
    @ManyToOne
    @JoinColumn(name = "maKh")
    @MapsId(value = "maKh")
    private KhachHang khachHang;
    @ManyToOne
    @JoinColumn(name = "maMay")
    @MapsId(value = "maMay")
    private May may;
}

如何获得客户名单包含列表SuDungMay和SuDungDichVu没有懒惰的错误，谢谢！`