{
    "label": "cmake",
    "type": "shell",
    "options": {
        "cwd": "${workspaceFolder}/build"
    },
    "command": "cmake \"MinGW Makefiles\"  ${workspaceFolder}",
},

这工作，它似乎是“在文件夹cpppractice执行任务：“是不准确的，它是在正确的地方执行它，至于为什么它以前没有工作，我认为它的解析参数不正确？我无法确认，但这是输出：

Executing task in folder cpppractice: cmake "MinGW Makefiles"  
C:\workspace\cpp\cpppractice <

-- Configuring done
-- Generating done
-- Build files have been written to: C:/workspace/cpp/cpppractice/build

以前它是compalining关于不能使用生成器“MinGW”这意味着它分离的参数“MinGW Makefiles”。经过一番修改，我发现这也是一个答案：

{
        "label": "cmake",
        "type": "shell",
        "options": {
            "cwd": "${workspaceFolder}/build"
        },
        "command": "cmake",
        "args": [
            "-G",
            "'MinGW Makefiles'",
            "./.."
        ],
        ...
    },

实际上我发现第二种方法更简洁一点，但两者的工作原理是一样的，所以为了将参数作为字符串传递，你必须使用单引号，如下所示：

...
"command":"echo",
"args": [
        "'Za Warudo!'",
    ],
...

错误地将参数传递给cmake。整个字符串cmake ${workspaceRoot} -G "MinGW Makefiles"被视为命令名。参数必须列在args数组中。

{
    "version": "2.0.0",
    "tasks": [
        {
            "label": "cmake",
            "type": "shell",
            "options": {
                "cwd": "${workspaceRoot}/build"
            },
            "command": "cmake",
            "args": [
                "${workspaceRoot}",
                "-G",
                "\"MinGW Makefiles\""
            ]
        },
        ...
    ]
}