我读到过，当我使用RabbitMQ时，最好的做法是每个进程使用一个连接，所以我想为rabbitmq连接创建一个单例类。我想使用Singleton的Lazy版本：在C#中实现Singleton模式
我写这个类：

public class RabbitConnection
{
    private static readonly Lazy<RabbitConnection>  Lazy = new Lazy<RabbitConnection>(() => new RabbitConnection());

    private RabbitConnection()
    {
        IConnectionFactory connectionFactory = new ConnectionFactory
        {
            HostName = "127.0.0.1",
            Port = 5672,
            UserName = "Username",
            Password = "********"
        };

        Connection = connectionFactory.CreateConnection();
    }

    public static RabbitConnection Instance
    {
        get { return Lazy.Value; }
    }

    public IConnection Connection { get; }
}

然后像这样使用：

var channel = RabbitConnection.Instance.Connection.CreateModel();
channel.QueueDeclare("myQueue", true, false, false, null);
....

这种实现方式是对还是错？谢谢你