多亏了杰里米，我才能和jq一起工作：jqlang.github.io/jq
我在下面的例子中使用reduce函数：blog.differentpla.net/blog/2019/01/11/jq-reduce
我最后的命令是：

type cs.json | jq ".instances.[] | {dataset: .attributes.DatasetId, company: .attributes.Company}" | jq  "reduce inputs as $line ({}; $line.company as $company | .[$company] as $current | $line.dataset as $bucket | $current[$bucket] as $count     | { ($bucket): ($count + 1) } as $this     | ($current + $this) as $next     | . + { ($company): ($next) }    )"

这给出了这样的JSON计数：

{
  "Acme Corp": {
    "Dataset A": 462,
    "Dataset B": 1
  },
  "Test Co": {
    "Dataset A": 1,
    "Dataset B": 1
  }
}