c++ 重叠cout [重复]

zpqajqem 于 2023-11-19 发布在其他

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此问题在此处已有答案：

Why does std::getline() skip input after a formatted extraction?（5个答案）
9天前关闭
由于某种原因，第二次循环时，cout语句会重叠。换句话说，在第一次cout之后，程序不会等待输入。我该如何解决这个问题？
另外，在真实的生活税的情况下，nPay函数工作正常吗？有人告诉我，税应该乘以总收入，每个单独的，并添加。然而，我的方法将工作相同，特别是因为它们同时发生。

double calcGrossPay (double payRate, double hours);
double nPay (double& fedTx, double& localTx, double& stateTx, double& ssTx, double& netPay, double fPay);
void displayAll (double fPay, double netPay, string name);

double fedTx = 14, stateTx = 6, localTx = 3.5, ssTx = 4.75;

int main()
{

    while (!cin.eof())
    {
          string name;

          //cin.ignore();
          cout <<"Please enter your working name: ";
          getline (cin, name);
          !cin.eof();

          double payRate, hours;

          cout <<"Enter your pay rate and hours worked, respectively."<< endl;
          cin >> payRate >> hours;
          !cin.eof();

          double fPay = calcGrossPay (payRate, hours);

          double netPay = 0;
          netPay = nPay (fedTx, localTx, stateTx, ssTx, netPay, fPay);
          displayAll (fPay, netPay, name);

           system("pause");
    }
}

double calcGrossPay (double payRate, double hours)
{
       double extraT, fPay;
       if (hours > 40)
       {
       extraT = (hours - 40) * (1.5 * payRate);
       fPay = extraT + (40 * payRate);
       }
       else
       fPay = payRate * hours;

       return fPay;
}

double nPay (double& fedTx, double& localTx, double& stateTx, double& ssTx, double& netPay, double fPay)
{
       double totalTx = fedTx + localTx + stateTx + ssTx;
       netPay = fPay * (1 - (totalTx / 100));
       return netPay;
}

void displayAll (double fPay, double netPay, string name)
{
    cout <<"Below is "<< name << "'s salary information" << endl;

     cout << fixed << showpoint << setprecision(2) <<"\nYour calculated gross pay is $"
          << fPay << ", and your net pay is $" << netPay << endl;
}

字符串

c++

来源：https://stackoverflow.com/questions/20389017/overlapping-cout

2条答案

按热度按时间

gdx19jrr1#

在getline之后，一个新的行仍然在流中，所以你必须ignore它：

getline(cin, name);
cin.ignore();

字符串
此外，在检查流之前执行提取，而不是while (!cin.eof())：

while (getline(cin, name))
{
    cin.ignore();
    // ...
}

型
下面是更新后的代码。我希望它对你有用：

int main()
{
    for (std::string name; (cout << "Please enter your working name: ") &&
                            getline(cin >> std::ws, name);)
    {
        if (cin.eof())
            break;

        double payRate, hours;

        cout << "\nEnter your pay rate and hours worked, respectively." << endl;

        if (!(cin >> payRate >> hours))
            break;

        double fPay = calcGrossPay(payRate, hours);

        double netPay = nPay(fedTx, localTx, stateTx, ssTx, netPay, fPay);

        displayAll(fPay, netPay, name);
        cin.get();
    }
}

型

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7kqas0il2#

在Windows和MacOS中，在一行的末尾有一个回车字符（/r），当编译器读取\r时，它会将光标返回到该行的开头，如果你想避免这种情况发生，你可以通过阅读整个文件并在每次遇到它时将其设置为null（\0）来消除该字符。

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