没有现成的函数可以满足你的要求，所以你需要写一个函数。幸运的是，在这种情况下这并不太难--基本上你只需要从现有的数据中提取出你想要的数据片段来创建一个新的项目列表。

import json

json_response = """\
    {
        "status": 200,
        "errmsg": "OK",
        "data": {
            "total": 12,
            "items": [{
                    "id": 11,
                    "name": "BBC",
                    "priority": 4,
                    "levelStr": "All",
                    "escalatingChainId": 3,
                    "escalatingChain": {
                        "inAlerting": false,
                        "throttlingAlerts": 20,
                        "enableThrottling": true,
                        "name": "Example123",
                        "destination": [],
                        "description": "",
                        "ccdestination": [],
                        "id": 3,
                        "throttlingPeriod": 10
                    }
                },
                {
                    "id": 21,
                    "name": "CNBC",
                    "priority": 4,
                    "levelStr": "All",
                    "escalatingChainId": 3,
                    "escalatingChain": {
                        "inAlerting": false,
                        "throttlingAlerts": 20,
                        "enableThrottling": true,
                        "name": "Example456",
                        "destination": [],
                        "description": "",
                        "ccdestination": [],
                        "id": 3,
                        "throttlingPeriod": 10
                    }
                }
            ]
        }
    }
"""

response = json.loads(json_response)

cleaned = []
for item in response['data']['items']:
    cleaned.append({'id': item['id'],
                    'name': item['name'],
                    'priority': item['priority'],
                    'levelStr': item['levelStr'],
                    'escalatingChainId': item['escalatingChainId'],
                    'escalatingChainName': item['escalatingChain']['name']})

print('cleaned:')
print(json.dumps(cleaned, indent=4))

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您可以尝试：

data = {
    "status": 200,
    "errmsg": "OK",
    "data": {
        "total": 12,
        "items": [{
                "id": 11,
                "name": "BBC",
                "priority": 4,
                "levelStr": "All",
                "escalatingChainId": 3,
                "escalatingChain": {
                    "inAlerting": False,
                    "throttlingAlerts": 20,
                    "enableThrottling": True,
                    "name": "Example123",
                    "destination": [],
                    "description": "",
                    "ccdestination": [],
                    "id": 3,
                    "throttlingPeriod": 10
                }
            },
            {
                "id": 21,
                "name": "CNBC",
                "priority": 4,
                "levelStr": "All",
                "escalatingChainId": 3,
                "escalatingChain": {
                    "inAlerting": False,
                    "throttlingAlerts": 20,
                    "enableThrottling": True,
                    "name": "Example456",
                    "destination": [],
                    "description": "",
                    "ccdestination": [],
                    "id": 3,
                    "throttlingPeriod": 10
                }
            }
        ]
    }
}

for single_item in data["data"]["items"]:
    print(single_item["id"])
    print(single_item["name"])
    print(single_item["priority"])
    print(single_item["levelStr"])
    print(single_item["escalatingChain"]["inAlerting"])
    # and so on

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有两种方法可以实现这一点，这取决于你是使用python列表和字典理解来处理变量还是.json文件：
1.其中字典（嵌套）类型的数据变量已经定义：

# keys you want
to_keep = ['id', 'name', 'priority', 'levelStr', 'escalatingChainId',
           'escalatingChainName']
new_data = [{k:v for k,v in low_dict.items() if k in to_keep}
            for low_dict in data['data']['items']]
# where item is dictionary at lowest level
escalations = [{v+'Name':k[v]['name']} for k in data['data']['items']
                                        for v in k if type(k[v])==dict]
# merge both lists of python dictionaries to produce flattened list of dictionaries
new_data = [{**new,**escl} for new,escl in zip(new_data,escalations)]

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1.或者（由于您引用了json包）如果您将响应保存为.json文件：

import json

with open('response.json', 'r') as handl:
    data = json.load(handl)
to_keep = ['id', 'name', 'priority', 'levelStr', 'escalatingChainId',
           'escalatingChainName']
new_data = [{k:v for k,v in low_dict.items() if k in to_keep}
                     for low_dict in data['data']['items']]
escalations = [{v+'Name':k[v]['name']} for k in data['data']['items']
                                         for v in k if type(k[v])==dict]
new_data = [{**new,**escl} for new,escl in zip(new_data,escalations)]

型
两者都产生输出：

[{'id': 11,
  'name': 'BBC',
  'priority': 4,
  'levelStr': 'All',
  'escalatingChainId': 3,
  'escalatingChainName': 'Example123'},
 {'id': 21,
  'name': 'CNBC',
  'priority': 4,
  'levelStr': 'All',
  'escalatingChainId': 3,
  'escalatingChainName': 'Example456'}]

型

有一个更好的方法来做到这一点，通过使用像这样的generator：

def item_generator(json_input, lookup_key):
    if isinstance(json_input, dict):
        for k, v in json_input.items():
            if k == lookup_key:
                yield v
            else:
                yield from item_generator(v, lookup_key)
    elif isinstance(json_input, list):
        for item in json_input:
            yield from item_generator(item, lookup_key)

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这将调用一个递归调用，并给予您想要的key值，即使代码之间有列表。只需使用如下函数调用它：

for j in item_generator(p_d, i):
        {}

print(output)

型