**THE SHORT ANSWER：**首先需要将转义的字符串反编译为目标类型，但不是反编译为目标类型，而是反编译为另一个字符串（必要时重复）;然后，它被反编译为目标类型：

// Initial example json string:  "\"{\\\"Property1\\\":1988,\\\"Property2\\\":\\\"Some data :D\\\"}\""

// First, deserialize to another string (unescaped string).
string unescapedJsonString = JsonConvert.DeserializeObject<string>(escapedJsonString);
Debug.WriteLine(unescapedJsonString);
// Prints:
// "{\"Property1\":1988,\"Property2\":\"Some data :D\"}"

// Second, deserialize to another string, again (in this case is necessary)
var finalUnescapedJsonString = JsonConvert.DeserializeObject<string>(unescapedJsonString);
Debug.WriteLine(finalUnescapedJsonString);
// This time prints a final, unescaped, json string:
// {"Property1":1988,"Property2":"Some data :D"}

// Finally, perform final deserialization to the target type, using the last unescaped string.
MyClass targetObject = JsonConvert.DeserializeObject<MyClass>(finalUnescapedJsonString);

字符串

**LONG ANSWER（但很有趣）**使用string.Replace(...可能会生成一个无效的字符串，因为它可能会损坏某些需要反斜杠正确表示的特殊字符。

这种类型的转义字符串通常是在已经是JSON字符串的字符串再次序列化时生成的（甚至更多次）。这会导致类似“各种级别的序列化”的情况。（它实际上是一个带有保留字符的字符串的序列化），结果是反哈希字符（或一组，两个或多个反斜杠：\，\，\）分散在字符串中。因此，正确地删除它们并不足以将它们替换为空。

正确的方法：获得未转义字符串的更好方法是首先将其转换为字符串类型（如果需要，请重复多次），然后将其转换为目标字符串类型：

// -- SERIALIZATION --

// Initial object
MyClass originObj = new MyClass { Property1 = 1988, Property2 = "Some data :D" };

// "First level" Of serialization.
string jsonString = JsonConvert.SerializeObject(originObj);
Debug.WriteLine(jsonString);
// Prints: 
// {"Property1":1988,"Property2":"Some data :D"}

// "Second level" of serialization.
string escapedJsonString = JsonConvert.SerializeObject(jsonString);
Debug.WriteLine(escapedJsonString);            
// "{\"Property1\":1988,\"Property2\":\"Some data :D\"}"
// Note the initial and final " character and de backslash characters

// ...
// at this point you could do more serializations ("More levels"), Obtaining as a result more and more backslash followed,
// something like this:
// "\"{\\\"Property1\\\":1988,\\\"Property2\\\":\\\"Some data :D\\\"}\""
// Note that is... very very crazy :D
// ...

// -- DESERIALIZATION --

// First deserialize to another string (unescaped string).
string unescapedJsonString = JsonConvert.DeserializeObject<string>(escapedJsonString);
Debug.WriteLine(unescapedJsonString);
// Prints:
// {"Property1":1988,"Property2":"Some data :D"}

// ...
// at this point you could repeat more deserializations to string, if necessary. For example if you have many backslash \\\
// ...

// Finally, perform final deserialization to the target type, using the last unescaped string.
MyClass targetObject = JsonConvert.DeserializeObject<MyClass>(unescapedJsonString);

型

在重新配置过程之前尝试string contentCorrected = contentCorrected.Replace(@"\", "");。

当答案中使用了有效的双引号时，就会出现问题。删除和/或替换并不能在所有情况下解决这个问题。我也很沮丧，直到我找到了一个简单的解决方案：

var billList = JsonConvert.DeserializeObject<List<Dictionary<string, string>>>(@contentCorrected);

字符串

1.删除所有\字符，然后再重新格式化。使用替换函数。

yourJsonString.Replace("\\\\\\\\\", "");

字符串
2.您的JSON字符串不完整或似乎不是List<Dictionary<string, string>>"类型。请更正您希望转换的JSON类型。我对您的JSON进行了如下修改，并成功运行。

newJson = "{\"array\":" + yourJsonString + "}"

型

对我来说，下面的代码工作

string contentCorrected = contentCorrected.Replace(@"\""", "");

字符串