我有以下3个django模型(使用一些抽象):
class Person(models.Model):
full_name = models.CharField(max_length=120, validators=[MinLengthValidator(2)])
birth_date = models.DateField(default='1900-01-01')
nationality = models.CharField(max_length=50, default='Unknown')
class Meta:
abstract = True
class Director(Person):
years_of_experience = models.SmallIntegerField(validators=[MinValueValidator(0)], default=0)
objects = DirectorManager()
class Actor(Person):
is_awarded = models.BooleanField(default=False)
last_updated = models.DateTimeField(auto_now=True)
class Movie(models.Model):
MOVIE_GENRES = (
('Action', 'Action'),
('Comedy', 'Comedy'),
('Drama', 'Drama'),
('Other', 'Other')
)
title = models.CharField(max_length=150, validators=[MinLengthValidator(5)])
genre = models.CharField(max_length=6, choices=MOVIE_GENRES, default='Other')
rating = models.DecimalField(max_digits=3, decimal_places=1, validators=[MinValueValidator(0.0), MaxValueValidator(10.0)], default=0)
director = models.ForeignKey(Director, on_delete=models.CASCADE)
starring_actor = models.ForeignKey(Actor, on_delete=models.SET_NULL, blank=True, null=True)
actors = models.ManyToManyField(Actor, related_name="actors")
字符串
正如你在上面的代码中看到的,我也有1个经理。这里是:
class DirectorManager(models.Manager):
def get_directors_by_movies_count(self):
return self.all().values("full_name").annotate(movies_num=Count("movie__director")).order_by("-movies_num", "full_name")
型
这是我的问题。我需要和输出像这样:
<QuerySet [<Director: Francis Ford Coppola>, <Director: Akira Kurosawa>...>
型
相反,我收到了这个:
<QuerySet [{'full_name': 'Francis Ford Coppola', 'movies_num': 2}, {'full_name': 'Akira Kurosawa', 'movies_num': 1}...]>
型
所以,我只需要一个记录:Director,而不是这两个full_name和movies_num,但我想保留相同的组和顺序逻辑。如何做到这一点?
1条答案
按热度按时间gajydyqb1#
不要使用
.values()
,它将模型对象转换为字典,这也是一个primitive obsession antipattern [refactoring.guru]:字符串