尝试以下 * 捕获模式 *。

\"url\"\s*:\s*\".+?/(.+?)(?<!\\)\"

字符串

URL后的所有内容/

如果你只是想要那个特定URL的.com/之后的所有内容-这是你所要求的，但可能不是你真正想要的，那么就这样做：

import json

json_data = '{"url":"www.mysite.com/4c344ce1-c6b5-497a-a8da-f4dfbc9f3668"}'

data = json.loads(json_data)
pattern = r'com\/(.*)'

match = re.search(pattern, data['url'])

# Check if the pattern is found
if match:
    # Access the captured group using group(1)
    uuid_group = match.group(1)
    print("Pattern found:", uuid_group)
else:
    print("Pattern not found")

字符串

提取url中的第一个uuid

pattern = r'[a-fA-F0-9]{8}-[a-fA-F0-9]{4}-[a-fA-F0-9]{4}-[a-fA-F0-9]{4}-[a-fA-F0-9]{12}'

match = re.search(pattern, data['url'])

# Check if the pattern is found
if match:
    # Access the captured group using group(1)
    uuid_group = match.group(0)
    print("Pattern found:", uuid_group)
else:
    print("Pattern not found")

型