下面是我得到的错误截图。
的数据
登录中使用的LoginController代码如下所示
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;
use Hash;
use App\Models\Customer;
class LoginController extends Controller
{
public function login(){
return view('user.login');
}
public function check(Request $request)
{
$credentials= $request->validate([
'username' => ['required'],
'password' => ['required'],
]);
if(Auth::attempt([$credentials])){
return view('welcome');
}
else{
return view('unauth');
}
}
}字符串
Customer.php模型如下所示
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
class Customer extends Model
{
use HasFactory;
protected $fillable=[
'name',
'username',
'password',
'email',
'invoice',
'kwh',
'warranty',
'date'
];
}型
web.php中的代码如下所示
Route::get('/login', [LoginController::class,'login']);
Route::post('/check',[LoginController::class,'check'])->name('check');
Route::get('/unauthorizedaccess', function () {
return view('unauth');
});型
Login.blade.php代码如下
<!doctype html>
<html lang="en">
<head>
<!-- Required meta tags -->
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- Bootstrap CSS -->
<link href="https://cdn.jsdelivr.net/npm/[email protected]/dist/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-EVSTQN3/azprG1Anm3QDgpJLIm9Nao0Yz1ztcQTwFspd3yD65VohhpuuCOmLASjC" crossorigin="anonymous">
<link href="{{asset('css/customs.css')}}" rel="stylesheet" >
<title>Login Form</title>
</head>
<body style=" background-image: url({{url('img/img-1.webp')}});">
<div class="container-fluid">
<form action="{{ route('check') }}" method="POST" class="mx-auto formlogin">
{!! csrf_field() !!}
<div style="text-align: center;">
<img src="{{url('img/logo.webp')}}" alt="logo" width="170px;">
</div>
<div class="mb-3 mt-5">
<label for="exampleInputEmail1" class="form-label">Enter your Username</label>
<input type="text" name="username" class="form-control" required>
</div>
<div class="mb-3">
<label for="Password" class="form-label">Enter your Password</label>
<input type="password" name="password" class="form-control" required>
<a style="text-decoration: none;" href=""><div id="emailHelp" style="color: #0d6efd;" class="form-text mt-3">Forget password ?</div></a>
</div>
<button type="submit" name="submit" class="btn btn-primary mt-5">Login</button>
<div id="emailHelp" style="color:black; font-weight:600; text-align:center;" class="form-text mt-3 cus_mobile_issues">Don't Have an Account? <a style="text-decoration:none;" href="">Click Here</a></div>
</form>
</div>
<!-- Option 1: Bootstrap Bundle with Popper -->
<script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/js/bootstrap.bundle.min.js" integrity="sha384-MrcW6ZMFYlzcLA8Nl+NtUVF0sA7MsXsP1UyJoMp4YLEuNSfAP+JcXn/tWtIaxVXM" crossorigin="anonymous"></script>
</body>
</html>型
这些是与登录相关的文件。我不是LaravelMaven，我如何解决这个问题。提前谢谢你
1条答案
按热度按时间db2dz4w81#
在
Laravel中，Auth::attempt方法将尝试从Associative Array/Array of key-value pairs的Keys中获取列名，但当您传递Array时，由于它只有index，它将得到索引而不是键，键应该是一个列名。这就是为什么列名变成0和错误弹出。正如**@John Lobo提到的，
$request->validate已经返回了一个Associative Array**，但是你通过 Package 它Auth::attempt([$credentials])将它转换为Array。你可以简单地传递
$credentials而不 Package 它来解决这个问题。字符串