Binary floating point math is like this的一个。
但在这种情况下，您可以实现一个自定义的number formatter，例如：

public class DoubleFormatter : INumberFormatter2, INumberParser
{
    public virtual string Format { get; set; } = "{0:F2}"; // by default we use this but you can change it in the XAML declaration
    public virtual string FormatDouble(double value) => string.Format(Format, value);
    public virtual double? ParseDouble(string text) => double.TryParse(text, out var dbl) ? dbl : null;

    // we only support doubles
    public string FormatInt(long value) => throw new NotSupportedException();
    public string FormatUInt(ulong value) => throw new NotSupportedException();
    public long? ParseInt(string text) => throw new NotSupportedException();
    public ulong? ParseUInt(string text) => throw new NotSupportedException();
}

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注意：它没有记录AFAIK，但INumberFormatter2必须也实现INumberParser，否则你会得到更多外来的神秘错误的“无效参数”...
示例XAML：

<StackPanel>
    <StackPanel.Resources>
        <local:DoubleFormatter x:Key="df" /> <!-- change Format here -->
    </StackPanel.Resources>
    <NumberBox NumberFormatter="{StaticResource df}" Value="{x:Bind MyFloatValue, Mode=TwoWay}" />
</StackPanel>

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IIRC，这是NumberFormatter的问题。你能试试这个代码吗？

namespace NumberBoxExample;

// Customize the return values if you need to.
public class CustomIncrementNumberRounder : INumberRounder
{
    public double RoundDouble(double value) => value;

    public int RoundInt32(int value) => value;

    public long RoundInt64(long value) => value;

    public float RoundSingle(float value) => value;

    public uint RoundUInt32(uint value) => value;

    public ulong RoundUInt64(ulong value) => value;
}

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