如何编码：
参与人1总是掷骰子A，参与人B总是掷骰子B，比较结果5782次，也分别是A对C，B对C。
似乎我无法打印出骰子A更大，骰子B更大的次数，然后，骰子A和B具有相等的值。
问题是，显然，die_A_larger，die_B_larger和die_A_and_B_equal是未定义的。我想知道为什么以及如何解决这个问题。
到目前为止的代码：

import numpy as np

class die:
    def __init__(self, side_values=[1,2,3,4,5,6]):
        self.side_values = side_values

    def roll(self):
        i=np.random.randint(1,7)
        return self.sides[i]

#variables
A = die([3,3,3,3,3,6])
B = die([2,2,2,5,5,5])
C = die([1,4,4,4,4,4])
nmax = 5782

def count_number_of_wins(A, B):

    die_A_larger = 0
    die_B_larger = 0
    die_A_and_B_equal = 0

for n in range(nmax):
    if A > B:
        die_A_larger += 1
    elif A < B:
        die_B_larger +=1
    else:
        die_A_and_B_equal +=1
    
    return (die_A_larger, die_B_larger, die_A_and_B_equal)
print (count_number_of_wins(A, B))

def determine_best_die(dice):
    assert all(len(die) == 6 for die in dice)

    wins = [0] * len(dice)

    for i in range(len(dice)):
        for j in range(i+1, len(dice)):
            a, b = count_number_of_wins(dice[i], dice[j])
            if a > b:
                wins[i] = wins[i] + 1
            else:
                wins[j] = wins[j] + 1
    for i in wins:
        if (i == (len(dice)-1)):
            return wins.index(i)
    return -1

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